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2 answers:
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<h2>There are 45 houses on the left and require 95 plates, while there are 44 houses on the right and require 94 plates</h2>
Step-by-step explanation:
Houses are numbered from 1 to 99. So, there are 99 houses. Odd-numbered houses are on the left. So, there are 50 houses on the left, while there are 49 houses on the right.
For houses on left : The houses are numbered 1, 3, 5, 7, 9, 11, 13..... 97, 99
So 5 houses( 1, 3, 5, 7, 9) require only one plate for numbering, while the remaining 45 houses require 2 plates each. So total number of plates = =
plates.
For houses on right : The houses are numbered 2, 4, 6, 8, 10, 12, 14.... 96, 98
So 4 houses( 2, 4, 6, 8) require only one plate for numbering, while the remaining 45 houses require 2 plates each. So total number of plates = =
plates.
∴ There are 45 houses on the left and require 95 plates, while there are 44 houses on the right and require 94 plates.
Answer:
Part 1: 43.75%
Part 2: 44.07%
Step-by-step explanation:
Hello!
(Pt.1) First, set up a ratio . Next, you use long division I got the percent 43.75. After that, you subtract 6 from the girls group, (because of them moving away and then more coming back.) and 2 from the boys group. Then, you subtract those from the school "population" and you get 472 as the final population. So then you set up another ratio,
. I got a percent of 44.07% from that.
Thanks For Reading!