Incomplete question. However, let's assume this are feasible regions to consider:
Points:
- (0, 100)
- (0, 125)
- (0, 325)
- (1, 200)
Answer:
<u>Maximum value occurs at 325 at the point (0, 325)</u>
<u>Step-by-step explanation:</u>
Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.
- For point (0, 100): P= 2(0) + 1.5 (100) =150
- For point (0, 125): P= 2(0) + 1.5 (125) =187.5
For point (0, 325): P= 2(0) + 1.5 (325) = 487.5
For point (1, 200): P= 2(1) + 1.5 (200) = 302
Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.
Answer:
This is very detailed as I wish to make some principles about fractions clear.
3
5
12
Explanation:
This question boils down to
3
2
3
−
1
4
A fractions structure is that of:
count
size indicator of what you are counting
→
numerator
denominator
You can not directly add or subtract the counts (numerators) unless the size indicators (denominators) are the same.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Consider
3
2
3
Write as
3
+
2
3
Multiply by 1 and you do not change the value. However, 1 comes in many forms so you can change the way something looks without changing its true value
[
3
×
1
]
+
2
3
[
3
×
3
3
]
+
2
3
9
3
+
2
3
=
11
3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Putting it all together
3
2
3
−
1
4
→
11
3
−
1
4
But the size indicators are not the same. I chose to make them become 12
11
3
−
1
4
→
[
11
3
×
1
]
−
[
1
4
×
1
]
→
[
11
3
×
4
4
]
−
[
1
4
×
3
3
]
→
44
12
−
3
12
Now we may subtract the counts
→
44
−
3
12
=
41
12
But this is the same as
12
12
+
12
12
+
12
12
+
5
12
=
1
2
+
2
1
2
+
2
1
2
+
5
12
=
3
5
12
Step-by-step explanation:
Answer:
Step-by-step explanation:
184 in *2
To do this problem, you will need to know the side lengths of the triangle. If you have those, just plug them in for a, b, and c and evaluate the square root.
Here is an example. If the sides are 3, 4, 5.
It would be:
The 6 is in the formula because it is the semi-perimeter (half).
