We obtain the joint PMF directly from the joint MGF:
![\implies\mathrm{Pr}[X=x,Y=y]=\begin{cases}0.1&\text{for }x=y=0\\0.2&\text{for }x=1,y=0\\0.3&\text{for }x=0,y=1\\0.4&\text{for }x=y=1\\0&\text{otherwise}\end{cases}](https://tex.z-dn.net/?f=%5Cimplies%5Cmathrm%7BPr%7D%5BX%3Dx%2CY%3Dy%5D%3D%5Cbegin%7Bcases%7D0.1%26%5Ctext%7Bfor%20%7Dx%3Dy%3D0%5C%5C0.2%26%5Ctext%7Bfor%20%7Dx%3D1%2Cy%3D0%5C%5C0.3%26%5Ctext%7Bfor%20%7Dx%3D0%2Cy%3D1%5C%5C0.4%26%5Ctext%7Bfor%20%7Dx%3Dy%3D1%5C%5C0%26%5Ctext%7Botherwise%7D%5Cend%7Bcases%7D)
Then
![\mathrm{Pr}[X=Y]=\mathrm{Pr}[X=Y=0]+\mathrm{Pr}[X=Y=1]=0.1+0.4=\boxed{0.5}](https://tex.z-dn.net/?f=%5Cmathrm%7BPr%7D%5BX%3DY%5D%3D%5Cmathrm%7BPr%7D%5BX%3DY%3D0%5D%2B%5Cmathrm%7BPr%7D%5BX%3DY%3D1%5D%3D0.1%2B0.4%3D%5Cboxed%7B0.5%7D)
Answer:
I = 60 + 18k
Step-by-step explanation:
Data provided in the question:
The function for number of loaves, N that Moses bake
⇒ N(k) = 10 + 3k
here,
k is the kilograms of floor received
and,
Income in dollars, I(x) = 6x
here, x is the number of loaves baked
thus,
when k kilograms of flour is received,
x = N(k) = 10 + 3k
substituting x in income function,
we get
I = 6(10 + 3k)
or
I = 60 + 18k
D is .001. C is 1/1000.
To find b you have to do 5/6=x/100 and once you find that you can find a by moving the decimal over to the left two times
Answer:
Two terms
Step-by-step explanation:
First, we have to simplify reducing the number of terms, since there are like terms
x-5+16x+4-2x-3
Eventually, you'll get 15x-4, thus there are two terms.
Please correct me if I'm incorrect, and I'll change the answer, but I hope I helped :)
You can put each into standard form to see whether they have the right value.
5.5·10⁴ = 55,000 ≠ 0.00055
