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Dmitry_Shevchenko [17]
3 years ago
12

Solve the given system by the substitution method. If there is no solution or an infinite number of​ solutions, so state. Use se

t notation to express solution sets.
x+3y=14
4x+5y=35
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

x=5, y=3

Step-by-step explanation:

1) x+3y=14,4x+5y=35

2) x+3y=14

3) x=-3y+14

4) 4(-3y+14)+5y=35

5) -12y+56+5y=35

6) -7y+56=35

7) -7y=-21

8) y=3

9) x=-3\times 3+14

10) x=-9+14

11) x=5

finale and last : x=5,y=3 ✅

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JUST THE FIRST ONE EASY PLS ASAP
Sladkaya [172]

Answer:

<h2>For the first triangle, <u>x equals 22cm.</u></h2>

Here's how:-

x is the altitude or height of the triangle. To find it, we can use the Pythagoras theorem:-

altitude^{2} + base^{2} = hypotenuse^{2}

The base is 120cm and the hypotenuse is 122cm

Putting this in the equation, we get:-

altitude^{2} + 120^{2} = 122^{2}

altitude^{2} =  122^{2}-  120^{2}

altitude^{2} = 14884 - 14400

altitude^{2} = 484

altitude = \sqrt{484}

<h3>altitude = 22cm</h3><h2><u>So, x = 22cm</u></h2>

7 0
3 years ago
The sum of two consecutive integers is 201 find the integers
telo118 [61]

100 and 101

the two integers are n and n+1. this means that 2n+1=201. n=100 and n+1=101

8 0
3 years ago
Read 2 more answers
Help with number 9 please please thank you
Harlamova29_29 [7]

Answer:

\large\boxed{53.9ml=0.0539l}

Step-by-step explanation:

1l=1,000ml\to1ml=\dfrac{1}{1,000}l=0.001l\\\\\text{Therefore}\\\\53.9ml=53.9\cdot0.001l=0.0539l

6 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
4 years ago
Find the slope of the line that passes through the pair of points (4.5, 13.5) and (–3.5, –9).
Zigmanuir [339]
Given two points: (x₁,y₁) and (x₂,y₂) the slope "m" will be:
m=(y₁-y₂) / (x₁-x₂)                or                  m=(y₂-y₁) / (x₂-x₁)

In this case:
(4.5 , 13.5)
(-3.5 , -9)

m=(-9-13.5) / (-3.5-4.5)=-22.5 / -8=2.8125

Answer: the slope will be m=2.8125.
3 0
3 years ago
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