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Amanda [17]
3 years ago
15

Last year, Susan opened an investment account with $6800 . At the end of the year, the amount in the account had decreased by 6.

5% . How much is this decrease in dollars? How much money was in her account at the end of last year?
Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0
442 is the decrease
6358 money in her account at the end of last year
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duane and mick are saving their money to build a treehouse. duane adds $5 to their piggy bank every other week. mick adds $2 eve
levacccp [35]
10 weeks is the number of weeks they have been saving their money.

Duane = $5 every two weeks
Mick = $2 every week.

Get the value of Duane's weekly contribution = $5 / 2 = $2.5

Duane's share + Mick's share = $45
$2.5x  + $2.0x = $45   ===>> equation can also be x(2.5 + 2) = 45
$4.5x = $45
$4.5x / $4.5 = $45 / $4.5
x = 10 weeks.

To check:

$2.5(10) + $2(10) = $45
$25 + $20 = $45
<span>$45 = $45</span>
5 0
3 years ago
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Find the area for the figure below. Use 3.14 for pi.
Akimi4 [234]

Answer:

1228.31 mm^2

Step-by-step explanation:

The area for the circle is

(20^2*3.14)/2

The area for the rectangle

30*20

Total area

1228.31

6 0
2 years ago
Mrs. Viera spent $95.55 buying 13 pizzas for a class pizza party.
bixtya [17]

Answer:

it should be 7.35 for each pizza, sorry if it's wrong

Step-by-step explanation:

95.55 divided by 13 is 7.35

6 0
2 years ago
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What is the area of a triangle with vertices at (0, – 2), (8, – 2), and (9, 1)?
Luda [366]

<u>ANSWER:  </u>

The area of the triangle with vertices at (0, – 2), (8, – 2), and (9, 1) is 12 square units.

<u>SOLUTION: </u>

Given, vertices of the triangle are A(0, -2), B(8, -2) and C(9, 1).

We have to find the area of the given triangle.

We know that,

\text { Area of triangle }=\frac{1}{2}\left(x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right)

\text { Where, }\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right),\left(x_{3}, y_{3}\right) \text { are vertices of the triangle. }

Here in our problem, \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(0,-2),\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)=(8,-2) \text { and }\left(\mathrm{x}_{3}, \mathrm{y}_{3}\right)=(9,1)

Now, substitute the above values in the formula.

\text { Area of triangle }=\frac{1}{2}\left(x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right)

=\frac{1}{2}(0(-2-1)+8(1-(-2))+9(-2-(-2))

=\frac{1}{2}(0+8(1+2)+9(2-2))

\frac{1}{2}(0 + 0 +24) = \frac{24}{12} = 2

Hence, the area of the triangle is 12 sq units.

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Find the mean, median, and mode of the data set 8 2 7 2 6 5 ​
frutty [35]

Answer:

Mean is 6, median 5.5, mode 2

Step-by-step

3 0
2 years ago
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