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marysya [2.9K]
3 years ago
5

If p → q is true, then ~ p → ~ q is __________ true. always sometimes never

Mathematics
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:

The correct answer is Never

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You are lazy... do it on your own.
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Fred orders pictures from a photographer. Each picture costs $5.50. A one-time shipping fee of $4.25 is added to the cost of the
Alexus [3.1K]

Answer:

Fred ordered 12 pictures

Step-by-step explanation:

70.25-4.25 (one time shipping fee) =66

then you take 66 and divide it by the cost of each picture

66/5.50= 12 pictures

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What elements are found in the universal set but not in sets an or b?​
GaryK [48]

Answer:

Complement of a Set If U is a universal set and A is a subset of U, then the set of all elements in U that are not in A is called the complement of A and is denoted Ac.

Step-by-step explanation:

8 0
2 years ago
Write an arithmetic expression that calculates the average of 18 and 46. you may already know that: the average of two numbers i
Masteriza [31]

In this question , we have to write an arithmetic expression that calculates the average of 18 and 46.

TO find the average, we have to add the numbers and divide by 2.

So here we have to add 18 and 46 and divide by 2, that is

d = \frac{18+46}{2} = \frac{64}{2}

And that's the required algebraic expression .

8 0
3 years ago
300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A
Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0
3 years ago
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