Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
Answer:
$3934
Step-by-step explanation:
We know that the currency of different countries are different.
So, one US dollar = 1.23 Canadian dollar
Given : $3192
A trinidadian changed some US dollar to Canadian dollar who plans to visit Canada.
He exchanged $3192.
Therefore,
1 US dollar = 1.23 Canadian dollar
The value of $ 3192 will be equal to = 1.23 x 3192
= $ 3933.96
≈ $ 3934
Therefore, triodion received = $ 3934.
Answer: $800 because if you have a light that is $2,000 and it loses %10 of its price per month, and June is 4 months away, then it is only $800.
4 x .1 = .4 so $2,000 x .4 = $800
Another way to find or get help with an answer that will write out the problem and steps to find the answer is a free app called Photomath...
Answer:
wn work
Step-by-step explanation:
