What is the answer of 10-squareroot of 4 divided by 2

Find the value of x<br> 50<br> x

finlep [7]

The value of X is 80

6 0

3 years ago

What is the slope of the line that contains the points (9,-4) and (1, -5)

vlada-n [284]

Answer:

A. 1/8

Step-by-step explanation:

m = rise/run

m = (y2-y1)/(x2-x1)

m = (-5- - 4)/(1-9)

m = (-5+4)/(-8)

m = (-1)/(-8)

m = 1/8

5 0

3 years ago

Read 2 more answers

A researcher wants to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual

atroni [7]

Complete question is;

A researcher wants to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual containers are randomly assigned to two different groups. Plants in both groups are treated identically, except that the plants in group 1 are sprayed weekly with a kelp extract, while the plants in group 2 are not. After the first frost, 12 of the 50 plants in group 1 exhibited damage and 18 of the 50 plants in group 2 showed damage. Let p1 be the actual proportion of all tomato plants of this variety that would experience damage under the kelp treatment, and let p2 be the actual proportion of all tomato plants of this variety that would experience damage under the no-kelp treatment. Is there evidence of a decrease in the proportion of

tomatoes suffering frost damage for tomatoes sprayed with kelp extract? To determine

this, yo u test the hypotheses H0: p1 = p2, Ha: p1 < p2. The p - value of your test is

A) greater than 0.10.

B) between 0.05 and 0.10.

C) between 0.01 and 0.05.

D)between 0.001 and 0.01.

E) below 0.001.

Answer:

B) between 0.05 and 0.10.

Step-by-step explanation:

We are given;

Number of plants in group that exhibited damage = 12

Number of group 1 plants; n₁ = 50

Number of plants in group 2 that exhibited damage = 18

Number of group 2 plants; n₂ = 50

Proportion of plants in group 1 that exhibited damage; p₁^ = 12/50 = 0.24

Proportion of plants in group 2 that exhibited damage; p₂^ = 18/50 = 0.36

Pooled proportion; p¯ = (12 + 18)/(50 + 50) = 0.3

q¯ = 1 - p¯

q¯ = 1 - 0.3 = 0.7

Z-score will be;

z = ((p₁^ - p₂^) - 0)/√((p¯•q¯)×((1/n₁) + (1/n₂))

Plugging in the relevant values;

z = (0.24 - 0.36)/√((0.3 × 0.7) × ((1/50) + (1/50))

z = -0.12/0.092

z = -1.3

From z-distribution table attached, we have;

p-value = 0.0968

Correct answer is option B.

8 0

2 years ago

Please help....There are 42 boys and girls participating in an essay-writing competition. Of the competitors, 21 are in seventh

almond37 [142]

The probability of an 8th grader winning is : 14/42 which reduces to 1/3

the simulation would be : # 3 <====

because u will have 6 equal sections on ur spinner...with each section representing 7 people
one section representing 9th graders...so their is 7 of them
2 sections representing 8th graders....so their is 7 * 2 = 14 of them
and 3 sections representing 7th graders....7 * 3 = 21 of them

7 0

3 years ago

Read 2 more answers

In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a

Art [367]

Answer:

The answer is " $\bold{T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5}$ "

Step-by-step explanation:

Given value:

Temp-maximum= $18^{\circ}$

Temp. minimum = $3^{\circ}$

It is halfway between 10 am and 10 pm to 4 am.

The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:

$T = A \cos B(t-C) + D,$ where parameters are A, B , C, D, T is the ° C temperature and t is the time (1-24)