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gogolik [260]
3 years ago
13

If your budget was $1500 total, how many people can you invite? Write a similar equation and solve to find out how many guests y

ou could
invite with a total budget of $1500.
Mathematics
1 answer:
Andreyy893 years ago
6 0

Answer:

you can invite 3 members can

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Iris is a saleswoman whose base pay plus commissions amounted to
Anit [1.1K]

Answer:

Step-by-step explanation:

38% (Answer C)

Her $69,464 total pay was made up of $39,710 base pay and commissions.

Subtracting the latter figure from the former, we get $29,754, the amount of commissions Iris earned.

Determine what percentage of the $78,300 in sales is represented by this $29,754 in commissions:

 $29,754

--------------- * 100%  = 38% (Answer C)

 $78,300

7 0
4 years ago
Let y=f(x)=(3x+7)/(x-2) <br> find a rule for f^-1
Murrr4er [49]

Answer:

f^{-1}(x)=\frac{2x+7}{x-3}.

Step-by-step explanation:

The given function is f(x)=\frac{3x+7}{x-2},\:x\ne2.

We want to find a rule for f^{-1}(x).

Let y=\frac{3x+7}{x-2}.

Interchange x and y.

x=\frac{3y+7}{y-2}.

Solve for y.

x(y-2)=3y+7.

Expand

xy-2x=3y+7.

Group y-terms

xy-3y=7+2x.

Factor

(x-3)y=7+2x.

y=\frac{2x+7}{x-3}.

\therefore f^{-1}(x)=\frac{2x+7}{x-3},\:x\ne3.

8 0
3 years ago
Calculate the Volume<br> Pls help
elena-14-01-66 [18.8K]

Answer:

420

Step-by-step explanation:

Multiply length, times width, times height to get your answer.

7 times 12 times 5=420

3 0
3 years ago
Express the null hypothesis and the alternative hypothesis in symbolic form. The owner of a football team claims that the averag
Brilliant_brown [7]

Answer:

H_{0}: \mu \leq 63500\\H_A: \mu > 63500

Step-by-step explanation:

We are given the following in the question:

The owner of a football team claims that the average attendance at games is over 63,500.

He wants to justify that the team needs to be moved to a larger stadium outside the city.

If the attendance is larger than 63,500 the team would be moved to a larger stadium and if it is less than or equal to 63,500 that it would not.

Thus, the null and alternate hypothesis will be designed as:

H_{0}: \mu \leq 63500\\H_A: \mu > 63500

The null hypothesis says that the average attenders is equal to or less than 63,500 and alternate supports the claim that the attenders average is greater than 63,500.

4 0
3 years ago
-3j - (-4) over -6 = 12 j= ? ​
babymother [125]

Answer:

j =76/3

Step-by-step explanation:

-3j -  -4

------------------ = 12

-6

Multiply each side by -6 to clear the fraction

-3j +4

------------------ * -6 = 12 *-6

-6

-3j +4 = -72

Subtract 4 from each side

-3j +4-4 = -72 -4

-3j = -76

Divide each side by -3

-3j/-3 = -76/-3

j = 76/3

5 0
4 years ago
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