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olga55 [171]
3 years ago
5

Let y=f(x)=(3x+7)/(x-2) find a rule for f^-1

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

f^{-1}(x)=\frac{2x+7}{x-3}.

Step-by-step explanation:

The given function is f(x)=\frac{3x+7}{x-2},\:x\ne2.

We want to find a rule for f^{-1}(x).

Let y=\frac{3x+7}{x-2}.

Interchange x and y.

x=\frac{3y+7}{y-2}.

Solve for y.

x(y-2)=3y+7.

Expand

xy-2x=3y+7.

Group y-terms

xy-3y=7+2x.

Factor

(x-3)y=7+2x.

y=\frac{2x+7}{x-3}.

\therefore f^{-1}(x)=\frac{2x+7}{x-3},\:x\ne3.

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Describe the relationship between n and 4 that will make the value of the expression 7xn4greater than7
valina [46]

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To describe the relationship between n and 4.

"greater than" symbol is represented by '>'

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