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Nat2105 [25]
2 years ago
7

Intro to Solving Literal Equations and Formulas Picture Below:

Mathematics
1 answer:
guapka [62]2 years ago
3 0

Answer:

f/2 is the answers for the question

Step-by-step explanation:

please mark me as brainlest

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What is the value of x in 5x−3(x−11)=7(2x−5)+2
riadik2000 [5.3K]
The value of x is 5.5. I got this answer by first distributing -3 amongst (x-11), and distributing 7 amongst (2x-5). Next I combined like terms and subtracted 3x from 5x, and added -35 and 2. Next I subtracted 33 from both sides. Next I subtracted 14x from both sides. And finally I divided both sides by -12 to get the final answer of 5.5.
4 0
3 years ago
Evaluate the expression under the given conditions. tan(2); cos() = 5 13 , in quadrant i
Nataliya [291]

The solution to given expression tan(2θ) is 22.615°

For given question,

We have been given an expression tan(2θ)

Given that cos(θ) = 5/13, and θ is in quadrant 1.

We know that the trigonometric identity

sin²θ + cos²θ = 1

⇒ cos²θ = (5/13)²

⇒ sin²θ = 1 - 25/169

⇒ sin²θ = 169 - (25/169)

⇒ sin²θ = 144/169

⇒ sin(θ) = 12/13

We know that the identity cos(2x) = cos²x - sin²x

⇒ cos(2θ) = cos²θ - sin²θ

⇒ cos(2θ) = 25/169 - 144/169

⇒ cos(2θ) = -119/169

And sin(2x) = 2sin(x)cos(x)

⇒ sin(2θ) = 2sin(θ)cos(θ)

⇒ sin(2θ) = 2 × 12/13 × 5/13

⇒ sin(2θ) = 120/169

We know that, tan(x) = sin(x)/cos(x)

⇒ tan(2θ) = sin(2θ)/cos(2θ)

⇒ tan(2θ) = (120/169) / (-119/169)

⇒ tan(2θ) = 120 / (-119)

⇒ tan(2θ) = -1.008

Since θ is in quadrant 1, tan(2θ) = 1.008

⇒ 2θ = arctan(1.008)

⇒ 2θ = 45.23

⇒ θ = 22.615°

Therefore, the solution to given expression tan(2θ) is 22.615°

Learn more about the expression here:

brainly.com/question/14961928

#SPJ4

7 0
2 years ago
a certain bacteria populations doubles in size everyday. Suppose a sample starts with 500 bacteria. write an expression that mod
elena-14-01-66 [18.8K]

Answer:

16,000

Step-by-step explanation:

16,000 - answer

7 0
3 years ago
a fruit company delivers its fruit in two types of boxes large and small a delivery of five large boxes and two small boxes have
hodyreva [135]

Answer:

Large boxes:19 kg

Small boxes:5 kg

8 0
3 years ago
Answer each question and explain your reasoning.
SVETLANKA909090 [29]

Answer:

1. 30 mins

Step-by-step explanation:

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3 years ago
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