Answer:
155.3 m
Step-by-step explanation:
<u>We have:</u>
θ: is the angle measured from the vertical = 75 °
v = is the speed of the submarine = 10 m/s
t = 1 min
The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:
<u>Where:</u>
d: is the distance traveled by the submarine in 1 minute
x: is the deep to find
The distance, d, is:
Now, the deep is:

Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.
I hope it helps you!
5m+8 that’s it I’m pretty sure
Answer:

Step-by-step explanation:
Downtown Store North Mall Store
Sample size n 25 20
Sample mean
$9 $8
Sample standard deviation s $2 $1




Standard error of difference of means = 
Standard error of difference of means = 
Standard error of difference of means = 
Degree of freedom = 
Degree of freedom = 
Degree of freedom =36
So, z value at 95% confidence interval and 36 degree of freedom = 2.0280
Confidence interval = 
Confidence interval = 
Confidence interval = 
Hence Option A is true
Confidence interval is 
Answer:
its b
Step-by-step explanation:
Answer:

Step-by-step explanation:
<u>Electric Field</u>
The electric field produced by a point charge Q at a distance d is given by

Where

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.
Let's calculate the electric fields of each charge at the given point. The first charge
is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:


Similarly, for
, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:


Since E1 and E2 are opposite, the net field is the subtraction of both

