Earth's atmosphere is made up of a combination of gases. The major components of nitrogen, oxygen, and argon remain constant over time and space, while trace components like CO2 and water vapor vary considerably over both space and time.
Answer:
2.10 N
Explanation:
Draw a free body diagram of the toy. There are four forces:
Weight force mg pulling down,
Normal force N pushing up,
Friction force F pushing left,
Applied force 4.63 N pulling at an angle of 63.0°.
Sum of the forces in the x direction:
∑F = ma
4.63 N cos 63.0° − F = 0
F = 2.10 N
0.35 m/s^2. Its the difference of the two distances divided by the time. (12-5)/20
MARK ME BRAINLIEST PLEASE!!!!!
The total energy TE = mgh + 1/2 mU^2; where h = 20 m, g = 9.81 m/sec^2, and U = 10 mps. When the ball reaches max height H, all that TE will be potential energy PE = mgH = TE.
So there you are. TE = mgh + 1/2 mU^2 = mgH = TE from the conservation of energy. Solve for H.
1) H = (gh + 1/2 U^2)/g = h + U^2/2g = ? meters where everything on the RHS is given. You can do the math.
2) As the ball drops from H to h, it picks up KE as the potential energy mgH is converted when the potential energy is diminished to mgh, where h < H. So PE - pe = ke = mg(H - h) = 1/2 mv^2 so solve for v = sqrt(2g(H - h)) and, again, everything is given. You can do the math.
3) Same deal as 2) except now its V = sqrt(2gH) because all the PE = mgH = 1/2 mV^2 = KE when it is about to hit the ground. You can do the math.
Answer:
Angular speed of the stone at the moment of release, w = 12.55 rad/s
Explanation:
- The vertical distance (or Height) from the point where stone lands to the point of release = 28 m
- Radius of the circle on which the stone is whirled = R
- The horizontal distance from the point where stone lands to the point of release, d = 30*R
- Linear velocity is the product of radius of circle and the angular velocity of the rotation
Linear Velocity, v = R*w,
where w is the angular speed
Using the constant acceleration equation,
, where
- S is the vertical distance (in our case 28 m),
- u is the initial velocity (in our case 0 m/s),
- t is the time taken by stone to reach point X,
- a is the acceleration (in our case it will be g = 9.8 m/s)
Putting the values in our above constant acceleration equation we can find the time
,
(28) = (1/2)*(9.8)*t^2
t = 2.39 s
v = d/t
R*w = (30*R)/t
R*w*t = 30*R
w = 30/t
w = 30/2.39
w = 12.55 rad/s