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ad-work [718]
3 years ago
10

If a laser beam is red with a wavelength of 632.8 nm, what is the angle from the center of the airy disk to the first dark ring?

Physics
1 answer:
zheka24 [161]3 years ago
6 0

Answer

given,

wavelength of laser light = 632.8 nm

assuming that aperture of lens be equal to dia = 1 mm

now,

When laser light passes through aperture diffraction of light takes place

The first diffraction minima occurs at

        a sin (p) =\lambda

where a is the width of aperture

λ is the wavelength of light

p is the angle

        sin (p) =\dfrac{\lambda}{a}

        sin (p) =\dfrac{632.8\times 10^{-9}}{1 \times 10^{-3}}

        p =sin^{-1}(0.0006328)

               p = 0.0363° angle of the first dark ring

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An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to
Lana71 [14]

complete question:

An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to be 5°. What is the distance from the base of the cliff to the point on the ground? Round to the nearest foot

Answer:

a ≈  5281 ft

Explanation:

The observer at the top of a 462 ft cliff  measures the angle of depression from the top of the cliff to a point on the ground to be 5°.

The angle of depression form the top of the cliff = 5°

The 5° is outside the triangle formed . To find the angle in the triangle we have to subtract 5° from 90°.  90° - 5° = 85° Note sum of an angle on a right angle is 90°.  

using SOHCAHTOA  principle we can solve for the distance from the base of the cliff to the point on the ground(a)

tan  85° = opposite / adjacent

tan 85°  = a / 462

cross multiply

462 × tan 85° = a

a = 11.4300523 × 462

a =  5280.66  ft

a ≈  5281 ft

5 0
3 years ago
A car is moving with an initial relocity of
MA_775_DIABLO [31]

Answer:

The final acceleration of the car, v = 70 m/s

Explanation:

Given,

The initial velocity of the car, u = 20 m/s

The acceleration of the car, a = 10 m/s²

The time period of travel, t = 5 s

Using the I equations of motion

                     v = u + at

                        = 20 + 10(5)

                        = 20 + 50

                        = 70 m/s

Hence, the final acceleration of the car, v = 70 m/s

4 0
3 years ago
Which best esplains how the body maintains homeostasis.
Lisa [10]

a. all systems work together to stabilize the body

8 0
3 years ago
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Help me please I can't get the final step​
inna [77]

Answer:

\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}

Explanation:

<u>Dimensional Analysis</u>

It's given the relation between quantities A, B, and C as follows:

\displaystyle A=\frac{3}{2}B^mC^n

and the dimensions of each variable is:

A=L^2T^2

B=LT^{-1}

C=LT^2

Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n

Operating:

L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)

L^2T^2=L^{m+m}T^{-m+2n}

Equating the exponents:

m+n=2

-m+2n=2

Adding both equations:

3n=4

Solving:

n=4/3

m=2-4/3=2/3

Answer:

\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}

6 0
3 years ago
Please help me! Some people have proposed a new way to build houses in areas that are likely to experience tsunamis. In this des
Alla [95]

Answer:

house wouldn't have solid walls on all four sides. Instead, some of the wall areas would be replaced by substances that

water can travel through quickly, as shown in the diagram. How would this design help a house survive a tsunami? What

drawbacks might there be to this design?

Explanation:

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3 years ago
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