complete question:
An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to be 5°. What is the distance from the base of the cliff to the point on the ground? Round to the nearest foot
Answer:
a ≈ 5281 ft
Explanation:
The observer at the top of a 462 ft cliff measures the angle of depression from the top of the cliff to a point on the ground to be 5°.
The angle of depression form the top of the cliff = 5°
The 5° is outside the triangle formed . To find the angle in the triangle we have to subtract 5° from 90°. 90° - 5° = 85° Note sum of an angle on a right angle is 90°.
using SOHCAHTOA principle we can solve for the distance from the base of the cliff to the point on the ground(a)
tan 85° = opposite / adjacent
tan 85° = a / 462
cross multiply
462 × tan 85° = a
a = 11.4300523 × 462
a = 5280.66 ft
a ≈ 5281 ft
Answer:
The final acceleration of the car, v = 70 m/s
Explanation:
Given,
The initial velocity of the car, u = 20 m/s
The acceleration of the car, a = 10 m/s²
The time period of travel, t = 5 s
Using the I equations of motion
v = u + at
= 20 + 10(5)
= 20 + 50
= 70 m/s
Hence, the final acceleration of the car, v = 70 m/s
a. all systems work together to stabilize the body
Answer:

Explanation:
<u>Dimensional Analysis</u>
It's given the relation between quantities A, B, and C as follows:

and the dimensions of each variable is:



Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

Operating:


Equating the exponents:


Adding both equations:

Solving:


Answer:

Answer:
house wouldn't have solid walls on all four sides. Instead, some of the wall areas would be replaced by substances that
water can travel through quickly, as shown in the diagram. How would this design help a house survive a tsunami? What
drawbacks might there be to this design?
Explanation: