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ad-work [718]
4 years ago
10

If a laser beam is red with a wavelength of 632.8 nm, what is the angle from the center of the airy disk to the first dark ring?

Physics
1 answer:
zheka24 [161]4 years ago
6 0

Answer

given,

wavelength of laser light = 632.8 nm

assuming that aperture of lens be equal to dia = 1 mm

now,

When laser light passes through aperture diffraction of light takes place

The first diffraction minima occurs at

        a sin (p) =\lambda

where a is the width of aperture

λ is the wavelength of light

p is the angle

        sin (p) =\dfrac{\lambda}{a}

        sin (p) =\dfrac{632.8\times 10^{-9}}{1 \times 10^{-3}}

        p =sin^{-1}(0.0006328)

               p = 0.0363° angle of the first dark ring

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Use the diagram to answer the questions below.
svet-max [94.6K]

Answer:

1. because of the tilted axis of earth the seasons in northern hemisphere are the exact opposite of the southern. because the sunrays reaches the earth an different points and when the earth moves around the sun it changes the hemisphere which is tilted to the sun.

2. the northern hemisphere is in Winter and the southern in summer. because the southern is tilted to the sun and the northern not so less sunrays reaches the northern hemisphere.

I'm sorry my explanation are bad

4 0
3 years ago
solve the following system by any method 2x - 6y = 24 ... -5x + 6y = -6 ... A. (0,-6) B. (4,-1) C. (-6,-6) D. (6,-1)
vodka [1.7K]
Using elimination, the answer is C. 
5 0
4 years ago
What is the relationship between wavelength of light and the quantity of energy per photon?
slamgirl [31]

Answer:

The quantity of energy per photon is inversely proportional to the wavelength of the light.

Explanation:

Energy of light is given as

E = hf

where E = energy of the photons,

f = frequency of the light

If the number of photons = n

(E/n) = (h/n) f

Let (E/n) = E'

(h/n) = h'

But the frequency of light is related to wavelength through the relation

v = fλ

where v = speed of light = c

λ = wavelength of light

f = (c/λ)

E' = h' f

Substituting for f

E' = h' (c/λ)

h' and c are both constants, h'×c = K

E' = (K/λ)

So, the quantity of energy per photon is inversely proportional to the wavelength of the light.

Hope this Helps!!!

3 0
4 years ago
Read 2 more answers
A group of friends wants to go to the amusement park. They have no more
Mumz [18]

Answer:

p ≤ 8

Explanation:

Let's go over what we know that can help us build an inequality:

we know that these friends can spend no <em>more </em>than $325, meaning that they can either spend exactly $325, or they could spend less. This is our first clue, that one side of the inequality will be 325, and that the inequality sign will be <em>less than or equal to </em>( ≤ ) :

amount spent ≤ 325

Now, we want to figure out how many people can go (p)--but there's something we need to consider first--the parking.

Assuming that all friends take one car, we know we will have 11 dollars less to spend on admission (you can write this two ways).

amount spent on tickets + 11 ≤ 325

or, we can simplify it:

amount spent on tickets + 11 ≤ 325

                                          - 11     -11

amount spent on tickets ≤ 314

(I will be using the second way, you could always plug it back into the first way though)

now, we know that each "p" that we include will be multiplied by 39.25

         <em>Why?  Imagine we have one p (one person), they will cost 39.25, so we could write that as (p · 39.25) ,  ( 1· 39.25 ) -- we use × because that's how many </em><em>times</em><em> we're adding the number.  If we have two p, we could write it as (2p · 39.25)--there's an easier way to do this though</em>

<em />

So, we can write "p" to stand for all possible values of p possible,

p · 39.25 ≤ 314                  (we write this slightly differently):

39.25p ≤ 314          

Now, let's simplify!

   39.25p ≤ 314          

÷ 39.25     ÷ 39.25  (divide by 39.25 to isolate p)

          p   ≤   8

So, we know that the number of friends admitted must be less than or equal to 8, expressed as:

p ≤ 8

hope this helps! let me know if you need clarification on anything :)

5 0
2 years ago
Read 2 more answers
The temperature of the cosmic background radiation is measured to be 2.7 k. What is the wavelength of the peak in the spectral d
KATRIN_1 [288]

Answer:

1.07\cdot 10^{-3} m

Explanation:

The peak wavelength of the spectral distribution can be found by using Wien's displacement law:

\lambda=\frac{b}{T}

where

b=2.898\cdot 10^{-3} m\cdot K is Wien's displacement constant

T is the absolute temperature

For the cosmic background radiation, the temperature is

T = 2.7 K

So, the corresponding peak wavelength is

\lambda=\frac{2.898\cdot 10^{-3} m\cdot K}{2.7 K}=1.07\cdot 10^{-3} m

7 0
3 years ago
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