Given:
AB is the diameter of a circle.
m∠CAB = 26°
To find:
The measure of m∠CBA.
Solution:
Angle formed in the diameter of a circle is always 90°.
⇒ m∠ACB = 90°
In triangle ACB,
Sum of the angles in the triangle = 180°
m∠CAB + m∠ACB + m∠CBA = 180°
26° + 90° + m∠CBA = 180°
116° + m∠CBA = 180°
Subtract 116° from both sides.
116° + m∠CBA - 116° = 180° - 116°
m∠CBA = 64°
The measure of m∠CBA is 64°.
33.3% x 81
0.333 x 81
=26.973 answer
Just add 3 to both sides
x = 7
Answer:
f(x) = 3x^2 -21x +36
Step-by-step explanation:
The table gives the x- and y-intercepts, which are sufficient to write the equation in factored form. The x-intercepts of 3 and 4 tell you that factors are (x -3)(x -4). When x=0, this product is (-3)(-4) = 12, but the y-intercept value is 3 times that: 36. So, the factored equation is ...
f(x) = 3(x -3)(x -4)
Multiplying this out, we get ...
f(x) = 3(x^2 -7x +12)
f(x) = 3x^2 -21x +36