Take any 2 points through which the line on graph passes,
(0,-1) =(x₁,y₁)
& (2,-4)=(x₂,y₂)
slope=(y₂-y₁)/(x₂-x₁)
=[-4-(-1)]/(2-0)
=-3/2

Let

The curl is

where
denotes the partial derivative operator with respect to
. Recall that



and that for any two vectors
and
,
, and
.
The cross product reduces to

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

which means
is indeed conservative and we can find
.
Integrate both sides of

with respect to
and

Differentiate both sides with respect to
and




Now

and differentiating with respect to
gives




for some constant
. So

Answer:
p=1/8 q=3/4
Step-by-step explanation:
-2p+7q=5
-6p+35q=51/2
cancel out a variable
(-5)(-2p+7q=5)
-6p+35q=51/2
10p-35q=-25
-6p+35q=51/2 =
4p=1/2
4p/4=1/2 /4
p=1/8
substitute p=1/8 into one of the equation to find q
-2p+7q=5
-2(1/8)+7q=5
-1/4+7q=5
7q=5+1/4
7q=21/4
q= 21/4 /7
q=3/4