Answer:
Yellow smooth - 9
Yellow wrinkle - 3
Green smooth- 3
Green Wrinkle - 1
Explanation:
Let the green color of the seed be depicted by "G" and the yellow color of the seed be depicted by "g"
Let the smooth the seed be depicted by "R" and wrinkled seed be depicted by "r"
F1 cross -
true breeding smooth green plant ( RRGG) and true breeding wrinkled yellow (rrgg)
F1 gamete will be RG, RG, rg, rg
F1 offspring will be RrGg , Thus all F1 offspring will be heterozygous smooth and yellow.
Thus, R is dominant over r and g is dominant over G
F2 Generation –
RrGg x RrGg
Gametes will be RG, Rg, rG, rg
RG Rg rG rg
RG RRGG RRGg RrGG RrGg
Rg RRGg RRgg RrGg Rrgg
rG RrGG RrGg rrGG rrGg
rg RrGg Rrgg rrGg rrgg
R is dominant over r and g is dominant over G
Genotypes are –
RRGG - 1 (Smooth Green)
RRGg-2 (Smooth yellow)
RrGG-2 (Smooth Green)
RrGg-4 (Smooth yellow)
RRgg- 1 (smooth yellow)
Rrgg – 2 (Smooth yellow)
rrGG – 1 (wrinkled Green)
rrGg – 2 (Wrinkled yellow)
rrgg – 1 (wrinkled yellow)
Yellow smooth - 9
Yellow wrinkle - 3
Green smooth- 3
Green Wrinkle - 1
Ans.
A monohybrid cross can be defined as 'a cross between two individuals having different copies of a chromosome or gene of interest, which is responsible for variations in a single trait.'
These variations in a single trait are controlled by two or more alleles for a single chromosomes. For example, a cross between tall pea plant and dwarf pea plant to study the inheritance of plant height.
Thus, the correct answer is 'option). they differ in a single trait.'
<span>Answer D hop you get it </span><span>Answer</span>
