Answer:
V= area of cross-section x length
V = 0.5x(8x9) x 11
V = 396cm^3
Hope this helps!
Answer: You should cut out squares that are 4 inches by 4 inches.
One of the ways to do this problem is write and graph an equation. We can write an equation for the volume of this shape and then use a graphing calculator to graph it. If we look where the graph crosses 440, we will have our solution.
The volume needs to be 440. If we let x equal the side of the square that is cut out, we have the following dimensions.
Length = 19 - 2x
Width = 18 - 2x
Height = x
Volume = LWH
So our equation could be: y = (19 - 2x)(18 - 2x)x
If you graph that equation, it will intersect at the point (4, 440). Therefore, our square could be 4 by 4 inches.
Answer:
f(2) = 0
Step-by-step explanation:
Evaluate the function at x = 2.
f(x) = -3x^2 + 6x
f(2) = -3(2^2) + 6 * 2
f(2) = -3(4) + 12
f(2) = 0
Okay. Since the "y" value and 82* are on the same straight line, their values will always add up to make a sum of 180. So if you subtract 82 from 180 you get 98*. So your "y" value is equal to 98*.
Now, all of the degree values added together should give you a sum of 360, so now we must add the values we know, in order to find the "x" value. So, 112*+82*+98*=292. Now we know that the difference of 360 and 292 will give us the x value. So finally, 360-292=68. So your "x" value is equal to 68.
y=98
x=68
