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3 years ago

Help Me Please!!!!!!

Mathematics

2 answers:

denis23 [38]3 years ago

5 0

1.5 in standard form it’s 150000000000000

denis23 [38]3 years ago

4 0

The answer is going to be 1.5

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Determine the probability (as a decimal rounded to the nearest hundredth) of a normal random variable with a mean of three and a

mrs_skeptik [129]

Answer:

Step-by-step explanation:

On a normal distribution table with z scores of 0 as the mean and the standard deviations going to the right and to the left, 1.9 on the normal curve where 3 is the mean falls at -.275 on the normal curve where 0 is the mean. I used the normal distribution z table for negative values to get that .39165 lies to the left of -.275, which means that 1 - .39165 of the data lies to the right.

The probability that the value is greater than 1.9 is .60835, or as a percentage, 60.835%.

3 0

3 years ago

Find the x-intercept and the y-intercept<br><br> x - 2y = 6

Reptile [31]

Answer:

x-intercept = 6; y-intercept = 3

Step-by-step explanation:

To find the x-intercept, set y as 0 and solve for x.

To find the y-intercept, set x as 0 and solve for y.

7 0

3 years ago

Please help with this my please

Akimi4 [234]

Answer:

now i dont know if this is the thing your asking but a negative plus a negative is a positive.

3 0

3 years ago

Write an Equation using the following arithmetic sequence: 5, _____, ______, 32

Shalnov [3]

Answer:

The sequence is:

5, 14, 23, 32

Step-by-step explanation:

We know that an Arithmetic sequence with a₁ and the commo difference 'd' has the nth term such as:

aₙ = a₁ + (n-1)d

Given the arithmetic sequence

5, _____, ______, 32

here:

a₁ = 5

n = 4

aₙ

so substituting a₁ = 5, n = 4 and aₙ = 32 in the nth term

aₙ = a₁ + (n-1)d

32 = 5 + (4-1)d

32 = 5 + 3d

3d = 32-5

3d = 27

divide both sides by 3

3d/3 = 27/3

d = 9

Therefore, the common difference: d = 9

Determining the 2nd term:

Using the formula

aₙ = a₁ + (n-1)d

substitute n = 2, a₁ = 5, d = 9

a₂ = 5 + (2-1)9

a₂ = 5 + 1(9)

a₂ = 5 + 9

a₂ = 14

Determining the 3rd term:

Using the formula

aₙ = a₁ + (n-1)d

substitute n = 3, a₁ = 5, d = 9

a₃ = 5 + (3-1)9

a₃ = 5 + 2(9)

a₃ = 5 + 18

a₃ = 23

Thus, the sequence becomes:

5, 14, 23, 32

4 0

3 years ago

SAT scores are normally distributed with a mean of 1,500 and a standard deviation of 300. An administrator at a college is inter

Rama09 [41]

Answer:

The administrator should sample 968 students.

Step-by-step explanation:

We have to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.88}{2} = 0.06$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a p-value of $1 - 0.06 = 0.94$ , so Z = 1.555.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation of 300.

This means that $n = 300$

If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?

This is n for which M = 15. So

$M = z\frac{\sigma}{\sqrt{n}}$

$15 = 1.555\frac{300}{\sqrt{n}}$