Answer:
A
Step-by-step explanation:
Step-by-step explanation:
A question is asked with options for answers, but in reality, there is only one question stating that it is correct.
Answer:
centre = (2, - 3 ) and radius = 5
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
given
x² + y² - 4x + 6y - 12 = 0 ( add 12 to both sides )
x² + y² - 4x + 6y = 12 ( collect x/ y terms )
x² + 4x + y² + 6y = 12
using the method of completing the square
add ( half the coefficient of the x/ y terms )² to both sides
x² + 2(-2)x + 4 + y² + 2(3)y + 9 = 12 + 4 + 9
(x - 2)² + (y + 3)² = 25 ← in standard form
with (h, k ) = ( 2, - 3 ) and r =
= 5
Yes since 1/8 is equal to 4/32
Answer:

Step-by-step explanation:
we know that
To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.
we will proceed to verify each case to determine the solution of the problem
<u>case A)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y


Let


therefore
f(x) and g(x) are inverse functions
<u>case B)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y


Let


therefore
f(x) and g(x) are inverse functions
<u>case C)</u> ![f(x)=x^{5}, g(x)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B5%7D%2C%20g%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D)
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y
fifth root both members
![y=\sqrt[5]{x}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B5%5D%7Bx%7D)
Let

![f^{-1}(x)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D)
therefore
f(x) and g(x) are inverse functions
<u>case D)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y





Let



therefore
f(x) and g(x) is not a pair of inverse functions