Oh man i remember learning about this but i cant remember what the answer is i will see what I can do :D
The answer is: 'constrict the blood vessels in their large ears to reduce transfer of external heat to the blood in their ears.' This is an example of thermoregulation. Thermoregulation is the ability of the<span> </span>body to keep body temperature<span> within certain boundaries, even when the temperature of the surrounding environment is very different. The regulation of temperature by thermoregulating organisms is one aspect of </span>homeostasis. By using heat exchange systems, such as employed in this example, the animal will need to expend less energy on behavioural adaptations to maintain a constant body temperature.
<u>Answer</u>:
1.a) Species. It is the lowest taxon and represents the scientific name of the organism.
b) The species name is part of the binomial system of nomenclature developed by Linnaeus.
Thus it is composed of two parts each with its own writing rules (ex. gray wolf - <em>Canis lupus</em>):
A. the genus or generic name
- written first
- always underlined or italicized
- the first letter is always capitalized
ex. <em>Canis</em>
B. the specific epithet or species name
- is written second
- always underlined or italicized
- never capitalized
ex. <em>lupus</em>
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2. The results should always be the same. A dichotomous key is an identification tool based on a series of choices between alternative characters (dichotomous = divided into two parts). Thus, there is no room for subjective observation that may lead to another result. If the morphological traits of the organism are correctly identified, the the result should always be the same. Any differences occur due to errors on the scientist's part.
Answer:
43 monosaccharides will be joined together to make the complex carbohydrate.
Explanation:
The complex carbohydrates are synthesized by the joining of monosaccharide residues by glycosidic linkages.One glycosidic linkage joins two monosaccharide residues by the elimination of one molecule of water.
In other words it can be said that elimination of one water molecule joins two monosaccharides.By the same way elimination of 42 molecules of water will result in the joining of 43 monosaccaride residues.
