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3 years ago

Solve. 3/4x + 6 = 33 explain the work please :,)

Mathematics

2 answers:

Lyrx [107]3 years ago

6 0

Answer:

x=36

Step-by-step explanation:

first take six away from both sides to get 3/4x=27

then divide 27 by the numerator 3 to get 9. Then multiply 9 by the denominator 4 to get 36. So 3/4 of 36=27+6=33

LenKa [72]3 years ago

3 0

3/4x+6=33

We move all terms to the left:

3/4x+6-(33)=0

Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R

We add all the numbers together, and all the variables

3/4x-27=0

We multiply all the terms by the denominator

-27*4x+3=0

We multiply elements

-108x+3=0

We move all terms containing x to the left, all other terms to the right

-108x=-3

x=-3/-108

x=1/36

I hope this helps :)

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The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams. The combined weight of one die

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Answer:

The total weight of one die, one ball, and one marble is 75 grams.

Step-by-step explanation:

Consider the provided information.

Let d represents the number of dice, b represents the number of balls and m represents the number of marbles.

So according to the question.

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams.

$2d+5b+4m=260$ ....(1)

The combined weight of one die and one marble was 55 grams.

$d+m=55$

$m=55-d$ ....(2)

3 balls weighed the same as two dice.

$3b=2d$

Multiply both sides by 5 and divide by 3.

$5b=\frac{10}{3}d$ .....(3)

Now put the value of equation 2 and 3 in equation 1.

$2d+\frac{10}{3}d+4(55-d)=260$

$2d+\frac{10}{3}d+220-4d=260$

$\frac{6d+10d-12d}{3}=40$

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Put d=30 in equation 2.

$m=55-30$

$m=25$

Put d=30 in equation 3.

$5b=\frac{10}{3}\times 30$

$5b=100$

$b=20$

The total weight (in grams) of one die, one ball, and one marble is:

$d+m+b=25+20+30$

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The total weight of one die, one ball, and one marble is 75 grams.

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