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Semmy [17]
3 years ago
9

Highest common factor of 275 and 350?​

Mathematics
2 answers:
Nata [24]3 years ago
7 0

25 is the answer

G00Gle auntuy is free u can ask fa her also

I took her help

thank her..xd

Ksenya-84 [330]3 years ago
7 0

Answer:

25

Step-by-step explanation:

Factors of,

275 = 1, 5, 11, 25, 55, 275

350 = 1, 2, 5, 10, 7, 14, 25, 35, 50, 70, 175, 350

Highest common factor of 275 and 350 is 25.

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Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl
Karo-lina-s [1.5K]

Full Question

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordless, and the other six are corded phones. Suppose that these components are randomly allocated the numbers 1, 2, . . . , 18 to establish the order in which they will be serviced.

What is the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced?

What is the probability that two phones of each type are among the first six serviced?

Answer:

a. 0.149

b. 0.182

Step-by-step explanation:

Given

Number of telephone= 18

Number of cellular= 6

Number of cordless = 6

Number of corded = 6

a.

There are 18C6 ways of choosing 6 phones

18C6 = 18564

From the Question, there are 3 types of telephone (cordless, Corded and cellular)

There are 3C2 ways of choosing 2 out of 3 types of television

3C2 = 3

There are 12C6 ways of choosing last 6 phones from just 2 types (2 types = 6 + 6 = 12)

12C6 = 924

There are 2 * 6C6 * 6C0 ways of choosing none from any of these two types of phones

2 * 6C6 * 6C0 = 2 * 1 * 1 = 2.

So, the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced is

3 * (924 - 2) / 18564

= 3 * 922/18564

= 2766/18564

= 0.149

b)

There are 6C2 * 6C2 * 6C2 ways of choosing 2 cellular, 2 cordless, 2 corded phones

= (6C2)³

= 3375

So, the probability that two phones of each type are among the first six serviced is

= 3375/18564

= 0.182

5 0
2 years ago
Which line is perpendicular to the line whose equation is 5y + 6 = -3x?
Lynna [10]

Answer: B

Step by Step

5y + 6 = -3X

5y = -3X - 6

Y = -3/5X -6/5

Perpedicular is the flip of your slope so -3/5 becomes 5/3X

6 0
3 years ago
What is the range of the function y = StartRoot x + 5 EndRoot?
Aleks [24]

Answer: y≤0

Step-by-step explanation:

Looking at the question, I'm assuming the equation is y=\sqrt{x+5}.

To find the range if this equation, it would be best to know that the graph of a square root looks like. Knowing that x=-5, the graph starts at -5 and then increases slowly to the right. Since there are no restrictions to this equation, the graph goes towards infinity.

8 0
3 years ago
Read 2 more answers
Help get brainiest if u help
valkas [14]

Answer:

32ft by 20ft

Step-by-step explanation:

8x4 and 5x4

8 0
2 years ago
Rafael can choose plan a or Plan B for his long-distance charges. For each plan, cost (in dollars) depends on minutes used (Per
PilotLPTM [1.2K]

Answer:

a. Plan B; $4

b. 160 mins; Plan B

Step-by-step explanation:

a. Cost of Plan A for 80 minutes:

Find 80 on the x axis, and trave it up to to intercept the blue line (for Plan A). Check the y axis to see the value of y at this point. Thus:

f(80) = 8

This means Plan A will cost $8 for Rafael to 80 mins of long distance call per month.

Also, find the cost per month for 80 mins for Plan B. Use the same procedure as used in finding cost for plan A.

Plan B will cost $12.

Therefore, Plan B cost more.

Plan B cost $4 more than Plan A ($12 - $8 = $4)

b. Number of minutes that the two will cost the same is the number of minutes at the point where the two lines intercept = 160 minutes.

At 160 minutes, they both cost $16

The plan that will cost less if the time spent exceeds 160 minutes is Plan B.

4 0
2 years ago
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