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tatyana61 [14]
3 years ago
11

Determine the principal value of the function: Arc sin(square root of 3/2)

Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Answer:

π/3

Step-by-step explanation:

We have to find the principal value of \text{arc sin}(\frac{\sqrt{3}}{2} )

arc sin means sin inverse. The sin inverse is a one to one function with its range between -\frac{\pi}{2} \textrm{ to } \frac{\pi}{2}

The principal value of the arc sin will lie within the above given range.

value of sin (60) or sin(\frac{\pi}{3}) is \frac{\sqrt{3}}{2}.

\frac{\pi}{3} lies between -\frac{\pi}{2}\textrm{ and } \frac{\pi}{2}

So, from here we can say that the Principal Value of Arc sin(square root of 3/2) is π/3

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line j is perpendicular to lines m and n. if the products of the slope of all three lines is -8, what is the slope of line j?
jeka94

Answer:

the slope of line j is -1/8, the slope of lines m and n are both 8.

Explanation step by step:

Suppose j is the slope of line j, m the slope of line m and n the slope of line n. Since:

1. line j is perpendicular of line m, so j*m= -1

2. J is perpendicular of line n, so  j*n=-1

3. m and n and parallel so m=n

As we want to know the slope of j we clear the equations presented to us in order to find it.

(1) m* n* j = -8, since n=m we have  n^{2}* j = -8.

we clear j; n^{2} * j = -8 \\ j =\frac{-8}{n^{2} }

replacing in the equation n*j = -1 we get

n*(-8/n^2) = -1. Thus n = 8. Since j = -1/n = -1/8.

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Step-by-step explanation:

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