(x4−3x3+4x2−8)/(x+1) = x3−4x2<span>+8x−8.</span>
Answer:
where am i supposed to find the x if you haven't given the equation for the sum
Step-by-step explanation:
No, these equations are not equivalent.
1/5, or one fifth, is part of a whole. Imagine you have a pie, cut into five pieces, and your friend comes over and eats four pieces, so now you have one of the five original pieces. That's what you have here.
5/5, or five fifths, is a whole. any number divided by itself is automatically one, so it is like making another pie and cutting it into five pieces, only this time no one eats any of it because it's burned or something. At the end, you have five pieces of pie
5/1 is actually just another way of writing plain old 5. To keep the pie example rolling, you have five pies, and no one eats any of these either, so they are all yours. You have 5 pies divided between one person, so at the end of the day you have 5 whole pies.
Hope that helped!
Since p is the midpoint then xp and pay must equal each other
So, 11-6b=6-b
Solve for b
11-6b=6-b
-6 -6
5-6b=-b
+6b +6b
5=5b
b=1
xp=11-6(1)
xp=5
A quadrilateral with two pairs of sides
