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Marina86 [1]
2 years ago
7

Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero.

Mathematics
1 answer:
uranmaximum [27]2 years ago
6 0

Step-by-step explanation:

just look what happened :

every term was multiplied by a factor with the value 1 (to keep the original value) but to establish a common denominator.

a/b was multiplied by d/d, and c/d was multiplied by b/b, so that the common denominator is then bd.

so, the first answer option is correct.

although I am a bit unhappy with its phrasing.

but the other options are definitely wrong.

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Pls help me I will give brainlyiest
storchak [24]

Answer:

57.72 in^2

Step-by-step explanation:

Question 1. Shapes are triangle, semi-circle, and rectangle.

Question 2.Find area of rectangle first. Then area of triangle and circle. Subtract area of triangle and circle. Then add the difference with the rectangles area.

Question 3.

Rectangle's area:<u>48 in^2</u>

Triangles area:8*4/2=  <u>16 in^2</u>

Circle Area: pi*r^2/2(since its a semi-circle)

3.14*2^2=3.14*4=12.56/2=<u>6.28 in^2</u>

Question 4.

16-6.28=9.72

9.72+48=57.72 in^2

5 0
2 years ago
Find the 9th term of the geometric sequence 9, 27, 81,
amm1812

Answer:

You have to multiply the last number by 3. So 9 times 3 equals 27 and 27 times 3 equals 81 and so on. The answer would be 59,049

Step-by-step explanation:

I hope this helps!!

5 0
3 years ago
How to graph the line y=4/3x
ankoles [38]

Answer:

make a table of values

Step-by-step explanation:

then plot using those values

3 0
3 years ago
Emma kept track of the number of puzzles solved during the past 10 days. She realized that she didn't solve any puzzles in the l
AveGali [126]
I think the answer is 13
6 0
3 years ago
Find the sum of the geometric series 40 + 40(1.005) + 40(1.005)^2 + ⋯ + 40(1.005)^11.
KiRa [710]

Answer:

The sum is 493.4

Step-by-step explanation:

In order to find the value of the sum, you have to apply the geometric series formula, which is:

\sum_{i=1}^{n} ar^{i-1} = \frac{a(1-r^{n})}{1-r}

where i is the starting point, n is the number of terms, a is the first term and r is the common ratio.

The finite geometric series converges to the expression in the right side of the equation. Therefore, you don't need to calculate all the terms. You can use the expression directly.

In this case:

a=40

b= 1.005

n=12 (because the first term is 40 and the last term is 40(1.005)^11 )

Replacing in the formula:

\frac{a(1-r^{n})}{1-r} = \frac{40(1-1.005^{12})}{1-1.005}

Solving it:

The sum is 493.4

4 0
3 years ago
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