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3 years ago

20 POINTS HELP ASAP

Mathematics

1 answer:

igomit [66]3 years ago

3 0

Answer: 17

Their all prime numbers so the next prime number is 17.

Step-by-step explanation:

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Look at this expression

vladimir2022 [97]

Answer:

OD22264 is the correct answer for that

4 0

3 years ago

Five rectangles are arranged from the least to the greatest area and named A, B, C, D, and E in order of increasing area. All di

Hatshy [7]

Given that median area is 15 square units.

Hence rectangle C in the middle has 15 square units.

Its dimensions can be width= 5 and length = 3

SInce B is smaller than C and has the same length, B has lengh of 3 with area = 9 sq units.

D has the same perimeter = 16 units. Since D is a square, side of D = 4 units.

Now D and E have the same length. Hence length of E = 4 units.

Width of E = width of C = 5 units.Thus makes the area of E as 20 sq units.

Rectangle A has length =3 and width can be less than 3 since area is smaller than B.

so A has length= 3 width = 2 with area = 6 sq units.

8 0

3 years ago

If Jenna walks 5 miles in 43 minutes, then how far will Jenna walk in 65 minutes? Round the answer to the nearest mile.

gavmur [86]

5 / 43 = x / 65....5 miles to 43 minutes = x miles to 65 minutes
cross multiply
(43)(x) = (65)(5)
43x = 325
x = 325/43
x = 7.55 rounds to 8 miles <===

4 0

3 years ago

Read 2 more answers

The mean number of hours per day spent on the phone, according to a national survey, is four hours, with a standard deviation of

Reika [66]

Answer:

The new mean is 5.

The new standard deviation is also 2.

Step-by-step explanation:

Let the sample space of hours be as follows, S = {x₁, x₂, x₃...xₙ}

The mean of this sample is 4. That is, $\bar x=\frac{x_{1}+x_{2}+x_{3}+...+x_{n}}{n}=4$

The standard deviation of this sample is 2. That is, $s=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}=2$ .

Now it is stated that each of the sample values was increased by 1 hour.

The new sample is: S = {x₁ + 1, x₂ + 1, x₃ + 1...xₙ + 1}

Compute the mean of this sample as follows:

$\bar x_{N}=\frac{x_{1}+1+x_{2}+1+x_{3}+1+...+x_{n}+1}{n}\\=\frac{(x_{1}+x_{2}+x_{3}+...+x_{n})}{n}+\frac{(1+1+1+...n\ times)}{n}\\=\bar x+1\\=4+1\\=5$

The new mean is 5.

Compute the standard deviation of this sample as follows:

$s_{N}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{n-1}\sum ((x_{i}+1)-(\bar x+1))^{2}\\=\frac{1}{n-1}\sum (x_{i}+1-\bar x-1)^{2}\\=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=s$

The new standard deviation is also 2.

5 0

4 years ago

Which ordered pair is the solution to the system of equations below when using the matrix tool?

boyakko [2]

The second one y bc I did this test already

4 0

3 years ago