Which are shown on a balance sheet? Select three choices. assets liabilities age time period date of birth

SAT

2 answers:

Bond [772]3 years ago

4 0

Assets, liabilities, time period should be shown on a balance sheet.

Balance Sheet are often regarded as financial statement that simply tells a brief summary of a company's assets, liabilities and shareholders' equity at a particular point in time.

Assets are said to be company's or individual's resource that is of economic importance corporation or that belongs or controled by country with the view that it will give future benefit.

From the above, we can therefore say that the answer Assets, liabilities, time period should be shown on a balance sheet is correct

Learn more from:

brainly.com/question/14314539

kirill115 [55]3 years ago

4 0

Answer:

A assets

B liabilitiies

D time period

You might be interested in

At x = 3, the function given by f(x)={x2 ,6x−9,x<3x≧3 is

ehidna [41]

Applying the definition, it is found that at $x = 3$ , the value of the function is 9.

The definition of the piece-wise function is:

$f(x) = x^2, x < 3$

$f(x) = 6x - 9, x \geq 3$

At x = 3, it enters the second definition, thus:

$f(3) = 6(3) - 9 = 18 - 9 = 9$

Thus, the value of the function is 9.

A similar problem is given at brainly.com/question/25029892

6 0

3 years ago

When looking at the night sky, many stars can be seen. What is true about all the stars seen in the night sky?

Vladimir [108]

B c and d. I think these are the answers

3 0

3 years ago

suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a

saul85 [17]

Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration, a= \frac{F}{m}a=mF

From the equation of motion,

\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)

In the second case, when mass is 2m, then acceleration,

a'=\frac{F}{2m}a′=2mF

and t' is the time taken.

The final speed is v,

\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

 I hope this is understandable and if my answer helped you please can you give me a brainliest its will really help me and thank you have a nice day!!