The least weight of a bag in the top 5 percent of the distribution is; 246
From the complete question below, we are given;
Population mean; μ = 240
Population standard deviation; σ = 3
Z-score formula is;
z = (x' - μ)/σ
- Now, we want to find the least weight in the top 5 of the distribution and as such we will use;
1 - 0.05/2 = 0.025 as significance level
Z-score at significance level of 0.025 is 1.96
Thus;
1.96 = (x' - 240)/3
3 × 1.96 = x' - 240
x' = 240 + 5.88
x' = 245.88
Approximating to a whole number gives;
x' = 246
Complete question is;
A machine is used to fill bags with a popular brand of trail mix. The machine is calibrated so the distribution of the weights of the bags of trail mix is normal, with mean 240 grams and standard deviation 3 grams. Of the following, which is the least weight of a bag in the top 5 percent of the distribution?
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Answer:
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Explanation:
The length of the base of the isosceles triangle is: 27 units long.
<h3>What is an isosceles Triangle?</h3>
A triangle with two equal legs and a base is called an isosceles triangle.
Thus:
Let x represent the length of each of the equal legs of the isosceles triangle.
Therefore:
The length of the base = 1 1/2(x) = 1.5x units
Perimeter = 63
Therefore:
x + x + 1.5x = 63
3.5x = 63
x = 63/3.5
x = 18
The length of the base = 1.5x units
Plug in the value of x
The length of the base = 1.5(18) = 27 units
Therefore, the length of the base of the isosceles triangle is: 27 units long.
Learn more about isosceles triangle on:
brainly.com/question/11884412
Explanation:
DO IT YOURSELF UGH NOT THIS WAY
