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Gekata [30.6K]
3 years ago
14

ASAP☑️☑️ Can you guys help me please

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0

Answer:

x = 9 , y =3

Step-by-step explanation:

-3x + y = 0 ---- 1

2x -2y = -12 -----2

By elimination method:

let's first eliminate x

we can do that by making x equal in both equations

multiply equation 1 by 2 ( because 2 is the coefficient of x in equation 2 and remember we want to equate both equations)

multiply equation 2 by -3 ( because -3 is the coefficient of x in equation 2 and remember we want to equate them both)

-3x + y = 0 ×2

2x -2y = -12 ×-3

-6x + 2y = 0 ----3

-6x + 6y = 36 -----4

subtract equation 4 from 3

that will give

0-4y = -36

which is

-4y = -36

divide both sides by coefficient of y which is-4

(-4y) ÷ (-4) = (-36)÷(-4)

answer : y= 9

substitute 9 for y in equation 1

-3x + y = 0

-3x + 9 = 0

subtract 9 from both sides

-3x +9-9= 0-9

-3x = -9

divide both sides by coefficient of x which is-3

(-3x)÷(-3) = (-9÷-3)

x = 3

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Andre45 [30]
<h3>Answer</h3>

First multiply everything by 27

-  \frac{4}{9} x =  \frac{16}{27}  =  \\ 27 \times ( -  \frac{4 }{9}x) = 27 \times  \frac{16}{27}

Then approximate the terms with 27 if it's possible (27 and 9) (27 and 27)

3 \times (   - \frac{4}{1} ) = 16

So now multiply again

3 \times ( - 4) =  - 12

And you have

- 12x = 16

x =  -  \frac{16}{12}  =  -  \frac{4}{3}

You're welcome if it's right

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