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Viktor [21]
3 years ago
10

What is the rate of change seen in the graph below?

Mathematics
1 answer:
Grace [21]3 years ago
7 0

Answer:

zero

Step-by-step explanation:

This flat horizontal line is Y=1 has a slope (rate of change) of zero.

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Find the area of the shape.
nikklg [1K]

Your question has been heard loud and clear.

Alright , so basically , the area of a circle formula = pi * R squared

R = radius = 4 units

Pi = 3.14

So , Area =  3.14 into 4 =  12.56 units

So Area of the circle = 12.56 units

Thank you

3 0
3 years ago
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77julia77 [94]

Answer:

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3 years ago
Consider the vector x: x <- c(2, 43, 27, 96, 18) Match the following outputs to the function which produces that output. Opti
Nookie1986 [14]

<u>Completed Question</u>

Outputs to be matched to the functions are:

  • 1,2,3,4,5
  • 1,5,3,2,4
  • 1, 4, 3, 5, 2
  • 2, 18, 27, 43, 96

Answer:

  • sort(x): 2, 18, 27, 43, 96
  • order(x): 1, 5, 3, 2, 4
  • rank(x) : 1, 4, 3, 5, 2
  • none of these :  1, 2, 3, 4, 5

Step-by-step explanation:

Given the vector x: x <- c(2, 43, 27, 96, 18)

<u>Sort</u>

In R, the sort(x)  function is used to arrange the entries in ascending or descending order. By default, R will sort the vector in ascending order.

Therefore, the output that matches the sort function is:

sort(x): 2, 18, 27, 43, 96

<u>Rank</u>

The rank function returns a vector with the "rank" of each value.

x <- c(2, 43, 27, 96, 18)

  • 2 has a rank of 1
  • 43 has a rank of 4
  • 27 has a rank of 3
  • 96 has a rank of 5
  • 18 has a rank of 2

Therefore, the output of rank(x)  is: 1, 4, 3, 5, 2

<u>Order</u>

When the function is sorted, the order function gives the previous location of each of the element of the vector.

Using the sort(x) function, we obtain: 2, 18, 27, 43, 96

In the vector: x <- c(2, 43, 27, 96, 18)

  • 2 was in the 1st position
  • 18 was in the 5th position
  • 27 was in the 3rd position
  • 43 was in the 2nd position
  • 96 was in the 4th position

Therefore, the output of order(x) is: 1, 5, 3, 2, 4

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3 years ago
Help me PLZZ it’s worth 20 points
Nonamiya [84]

Answer: uhhhhhhhhhhhhhhhhhhh whats the question?

Step-by-step explanation:

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3 years ago
What is the range of the function y = x2 +1 when the domain is {0, 2, 4}?
skad [1K]
You find the range by plugging 0 ,2 and 4 into x^2 + 1.

for x = 0   y = 0 + 1 = 1
  x = 2, y =  2^2 + 1 =  5
  x = 4  y =  4^2 + 1 =  17

so the range is  {1, 5, 17}
3 0
3 years ago
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