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1 year ago

13

Choose a reasonable estimate. The height of your kitchen table: 68 cm ? 68m

1 answer:

Mademuasel [1]1 year ago

8 0

Answer:

68 cm, 68 m is too big.

Step-by-step explanation:

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HELP ITS PAST DUE I WILL PICK BRALIEST!!!! (i dont know if i spelled that right)

Contact [7]

Correct: m,b,c
incorrect: a,n,c
it’s hard to explain

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2 years ago

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Thirty adults were asked how many pets they have had over their lifetime.

madam [21]

The statement that is most likely true is that the median is in the 6-10 interval and the mean is in the 6-10

There were a total of 30 different pieces of data collected, so the 15th and 16th pieces of data that would create the median. Both the 15th and 16th numbers would be in the 6 - 10.

If you find the average of the middle data point in each interval the mean would be approximately 7.2. This is in the 2nd interval (6-10).

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2 years ago

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Please this is urgent !

telo118 [61]

Answer:

the probability is very high 86% > 14%

Step-by-step explanation:

55+20+11= 86%/100% 100-86=14% chance there will not be any rain or lightning

hope this helps!!

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2 years ago

A child finds a cone-shaped pile of wet sand at the beach. She uses a bucket to move the sand pile to a different spot. The buck

Anika [276]

Answer:

Girl- Where's the radius and the heights of the cone tho-

Step-by-step explanation:

8 0

2 years ago

One of Julian's friends also has a rectangular aquarium. The dimensions of his friend's tank are each exactly 1 1/4 times the di

daser333 [38]

Answer:

468.75 square inches

Step-by-step explanation:

Let the length of Julian's tank be x

Let the width of Julian's tank be y

So, Area of Julian's tank= $Length \times Width =xy$

Since we are given that Julian's tank is approximately 300 square inches

So, $xy=300$ --1

Now we are given that The dimensions of his friend's tank are each exactly $1\frac{1}{4} =\frac{5}{4}$ times the dimensions of Julian's tank.

So,length of his friend's tank = $\frac{5}{4}x$

So,width of his friend's tank = $\frac{5}{4}y$

So, Area of his friend's tank= $\frac{5}{4}x \times \frac{5}{4}y$

= $\frac{25}{16}xy$

= $\frac{25}{16}(300)$ (Using 1)

= $468.75$

Hence the approximate area of the rectangular base of his friend's tank is 468.75 square inches.

So, Option D is correct.

8 0

2 years ago