The product of two perpendicular slopes is always -1
Answer:
-9/14
Step-by-step explanation:
This is my simplest-
Do the keep-change-flip method for this problem (and also any problem involving this)
KEEP -3/8
CHANGE the division sign to multiplication
FLIP the last fraction. 7/12 to 12/7
Now solve the problem by multiplying the fractions
-3/8 × 12/7 =
-3 × 12 = -36
8 × 7 = 56
-36 / 56 =
Simplify it by dividing the numerator (up of the line) and denominator (below the line) to get -9/14
Answer:
10
Step-by-step explanation:
20-(5×2)
5×2=10
20-10=10
The information given about the proof does that Daniel made an error on line 2.
<h3>How to illustrate the information?</h3>
Given:
1. AB = 3x +2; BC = 4x + 8; AC = 38
2. AB + BC = AC incorrect (not an angle angle addition postulate)
3. 3x+2 + 4x + 8 = 38 correct
4. 7x + 10 = 38 correct
5. 7x = 28 correct
6. x = 4
Daniel made an error on line 2.
Here is the complete question:
Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5
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The slope is 1/2 and the Y intercept is -3, so the equation will be Y=1/2x-3
