Area of the shaded region = area of big square minus area of little square.
Here is the set up:
Let A_s = area of shaded region.
A_s = (2x + 2)(3x - 4) - [(x - 3)(x - 6)]
Take it from here.
Mate, this answer may seem odd, but I tried four times, but first you want 1/4 as a decimal, and it would be 0.25. Now take that a dived 36, and you'll get 144<span />
(-4x2-5x-1)(4x2-6x-2)
Final result :
-2 • (13x + 1) • (2x2 - 3x - 1)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2".
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(-13x - 1) • ((22x2 - 6x) - 2)
Step 2 :
Pulling out like terms :
3.1 Pull out like factors :
-13x - 1 = -1 • (13x + 1)
Step 3 :
Pulling out like terms :
4.1 Pull out like factors :
(4x2 - 6x - 2) = 2 • (2x2 - 3x - 1)
Trying to factor by splitting the middle term
4.2 Factoring 2x2 - 3x - 1
The first term is, 2x2 its coefficient is 2 .
The middle term is, -3x its coefficient is -3 .
The last term, "the constant", is -1
Step-1 : Multiply the coefficient of the first term by the constant 2 • -1 = -2
Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is -3 .
-2 + 1 = -1
-1 + 2 = 1
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Step 4 :
Pulling out like terms :
5.1 Pull out like factors :
-26x - 2 = -2 • (13x + 1)
Final result :
-2 • (13x + 1) • (2x2 - 3x - 1)
It is 100 times smaller or 0.486 is 1/100th of 48.6
Answer:
1. Many possible solutions, two solutions would be: (-1,0) and (1,0)
2. x = −
2
± i
Step-by-step explanation:
For the first equation, since its linear, there are many possible solutions!
two solutions would be: (-1,0) and (1,0)
For the second one, replace y with 0 and solve
x = −2 ± <em>i</em>
<em />
<em>Hope i helped, brainliest would be appreciated</em>
<em>Have a nice day!</em>
<em> -Aadi x</em>
