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Aloiza [94]
2 years ago
6

There are 100 cents in a dollar what percent of a dollar is $0.15 a​

Mathematics
1 answer:
atroni [7]2 years ago
4 0
100=100%
15=X

15/100 x 100= 15%
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Need help with this. <br><br> A B C D
patriot [66]

Answer:

yes, it is a right triangle and ∡Q is the right angle

Step-by-step explanation:

if the slope of QR is the opposite reciprocal of QS then the two segments are perpendicular and form a 90° angle

slope of QR:  -3 - (-1) ÷ 2 - 0  = -2 ÷ 2 = -1

slope of QS:  -3 - (-1) ÷ 2 - 4  = -2 ÷ -2 = 1

-1 and 1 are opposite and reciprocal so m∡Q = 90°

8 0
3 years ago
I need help with this.
anyanavicka [17]

Answer:

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3 years ago
Can someone help me on this
Ierofanga [76]

1/2 of angle D is given as 32 degrees.

The 3 inside angles need to add up to 180 degrees.

Angle B is a right angle, which is 90.

Angle C = 180 - 90 - 32 = 58 degrees.

8 0
4 years ago
What is the coordinates for the given equation: y-2=-1/2 (x+6)
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Slope =1.000/2.000=0.5 X-intercept=10/-1=-10.0 Y-intercept=10/2=5
3 0
3 years ago
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
4 years ago
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