What kind of question is that? That’s a statement.
Answer: (-9,6)
Step-by-step explanation:
3x+2y=-15
2x=-18
First solve for x in second equation
2x=-18
2x/2=-18/2
X= -9
Now substitute your x into first equation to find y
3(-9)+2y= -15
-27+2y=-15
2y= -15+27
2y= 12
2y/2=12/2
Y= 6
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
Answer:
I think it would be
Sums
1) a + -5
2) m + -n
Differences
1) 7 - -3
2) a - -5
Step-by-step explanation:
Answer: 45 years old
Step-by-step explanation:
<u>Given:</u>
- Father's age is thrice the sum of ages of his two children
- After five years, his age will be twice the sum of their ages
Let x be the two children's current age and 3x be the father's current age
<u>Solve:</u>
Set equation
3x + 5 = 2 ( x + 10 )
Expand parenthesis
3x + 5 = 2x + 20
Subtract 5 on both sides
3x + 5 - 5 = 2x + 20 - 5
3x = 2x + 15
Subtract 2x on both sides
3x - 2x = 15
x = 15
15 × 3 = 45 years old
Hope this helps!! :)
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