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2 years ago

8

Use a graphing calculator to determine the solution of 1-2x - y = 2 13x + 2y=1

1 answer:

Arte-miy333 [17]2 years ago

6 0

The first one is 2x+y=-1

the second one is 13x+2y-1=0

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For an angle 0 with the point (-20,-21) on its terminating side, what is the value of cosine ?

Karo-lina-s [1.5K]

check the picture below.

$\bf (\stackrel{a}{-20},\stackrel{b}{-21})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{-20}\\ b=\stackrel{opposite}{-21}\\ \end{cases} \\\\\\ c=\sqrt{(-20)^2+(-21)^2}\implies c=\sqrt{841}\implies c=29 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-20}}{\stackrel{hypotenuse}{29}}~\hfill$

5 0

3 years ago

Please help me I dnt get it

yuradex [85]

The answer would be A and E because the distance (d) is more than 125 miles

8 0

3 years ago

Find the sum of the first 12 terms of the sequence. Show all work for full credit. 1, -4, -9, -14, . . . (2 points)

My name is Ann [436]

<u>Answer:</u>

$S_n=$ -348

<u>Step-by-step explanation:</u>

We are given the following arithmetic sequence and we are to find the sum of its first 12 terms:

1, -4, -9, -14, . . .

For that, we will use the formula for the sum of the arithmetic mean:

$S_n=\frac{n}{2} (a_1+a_n)$

We know the value of the first term ( $a_n$ ) but we need to find the value of $a_{12}$ . So we will use the following formula:

$a_{12}=a_1+(n-1)d$

$a_{12}=(-4)+(12-1)(5)$

$a_{12}=-59$

Substituting these values in the sum formula to get:

$S_n=\frac{12}{2} (1+(-59))$

$S_n=$ -348

4 0

3 years ago

Read 2 more answers

Juli2301 [7.4K]

Answer:

the answer is......

Step-by-step explanation:

f ,c,a

4 0

3 years ago

Read 2 more answers

Please answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

Oksanka [162]

Answer:

EF is parallel to HG or EH is parallel to FG. EF to HG is correct I think.

Step-by-step explanation:

Look at the markings on the lines.

7 0

2 years ago