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Liono4ka [1.6K]
3 years ago
15

If the length of the rectangle is twice the width and the perimeter of the rectangle is 30 cm, what is the length and width of t

he rectangle
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
4 0
The length of the rectangle is 10, while the width of the rectangle is 5.
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How many different ways can the letters in the word “square” be arranged ?
mr Goodwill [35]
It is known that 6 things can get arranged in 720 ways, let's look at the math of this.
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3 years ago
Write the standard form of the equation of a circle with radius 3 and center (11, 3)
Talja [164]

Answer:

<u>x² - 22x + y² - 6y + 121 = 0</u>

Step-by-step explanation:

<u>General Form of Equation</u>

  • (x - h)² + (y - k)² = r²

<u>Solving</u>

  • (x - 11)² + (y - 3)² = (3)²
  • x² - 22x + 121 + y² - 6y + 9 = 9
  • <u>x² - 22x + y² - 6y + 121 = 0</u>
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2 years ago
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I need help with this and the first person who can answer this correctly gets a BRANLIST​
Vesna [10]
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your answer is

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6 0
3 years ago
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A researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic
Delvig [45]

Answer:

90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

Step-by-step explanation:

We are given that a researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic meter with a standard deviation of 0.093.

Firstly, the pivotal quantity for 90% confidence interval for the population mean iron concentration is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean iron concentration = 0.802 cc/cubic meter

             s = sample standard deviation = 0.093

             n = number of water samples = 27

             \mu = population mean

<em>Here for constructing 90% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 90% confidence interval for the population mean, \mu is ;

P(-1.706 < t_2_6 < 1.706) = 0.90  {As the critical value of t at 26 degree of

                                                 freedom are -1.706 & 1.706 with P = 5%}

P(-1.706 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 1.706) = 0.90

P( -1.706 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 1.706 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X -1.706 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +1.706 \times {\frac{s}{\sqrt{n} } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X -1.706 \times {\frac{s}{\sqrt{n} } , \bar X +1.706 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 0.802 -1.706 \times {\frac{0.093}{\sqrt{27} } , 0.802 +1.706 \times {\frac{0.093}{\sqrt{27} } ]

                                                 = [0.771 , 0.832]

Therefore, 90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

4 0
3 years ago
I need help with questions 10-14, would appreciate work shown​
Nana76 [90]

Answer:

Step-by-step explanation:

10-h

11-A

12-g

13-a

14-f

Mark as brainlest please

8 0
3 years ago
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