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RideAnS [48]
3 years ago
12

HELP A CHICKEN NUGGET OUT!

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0
Here you go i hope this could help you

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Brianna recorded the high temperatures in her town each day for 8 consecutive days. Her data are shown. 78 , 65, 72 , 80, 68 , 7
scZoUnD [109]

Answer:

D)50% of the temperatures are less than 77.5 degrees

Step-by-step explanation:

The correct amount of temperatures that are less than 77.5 degrees is 6/8, or 75%.  So D) is false.

8 0
3 years ago
Use your line plot and answer the question below
Wittaler [7]

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Step-by-step explanation:

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3 years ago
How do you solve 3x^6- 39x^4+ 108x^2= 0
ArbitrLikvidat [17]
You can first take out an x^2 from each number , 3x^6 - 39x^4 + 108x^2 = x^2 ( 3x^4 - 39x^2 + 108) Then just factor and solve for the zero's of the equation
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3 years ago
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marta [7]
I think it’s the first answer AB and CD
6 0
3 years ago
Wholemark is an internet order business that sells one popular New Year greeting card once a year. The cost of the paper on the
erma4kov [3.2K]

Answer:

The optimal production quantity is 9,322 cards.

Step-by-step explanation:

The information provided is:

Cost of the paper = $0.05 per card

Cost of printing = $0.15 per card

Selling price = $2.15 per card

Number of region (n) = 4

Mean demand = 2000

Standard deviation = 500

Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

                                = $0.05 + $0.15

                                = $0.20

Compute the total demand as follows:

Total demand = Mean × n

                       = 2000 × 4

                       = 8000

Compute the standard deviation of total demand as follows:

SD_{\text{total demand}}=\sqrt{500^{2}\times 4}=1000

Compute the profit earned per card as follows:

Profit = Selling Price - Total Cost Price

         = $2.15 - $0.20

         = $1.95

The loss incurred per card is:

Loss = Total Cost Price = $0.20

Compute the optimal probability as follows:

\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}

                               =\frac{1.95}{1.95+0.20}\\\\=\frac{1.95}{2.15}\\\\=0.9069767\\\\\approx 0.907

Use Excel's NORMSINV{0.907} function to find the Z-score.

<em>z</em> = 1.322

Compute the optimal production quantity for the card as follows:

\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\

                                               =8000+(1.322\times 1000)\\=8000+1322\\=9322

Thus, the optimal production quantity is 9,322 cards.

8 0
3 years ago
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