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GalinKa [24]
1 year ago
15

21. For the following exercises, use the descriptions of each pair of lines given below to find the slopes of Line 1 and Line 2.

Is each pair of lines parallel, perpendicular, or neither?
21. Line 1: Passes through (1, 7) and (5, 5)
Line 2: Passes through (−1, −3) and (1, 1)
Mathematics
1 answer:
dybincka [34]1 year ago
6 0

Answer:

The given lines are perpendicular.

Step-by-step explanation:

In the question, two lines are given as line 1 passes through (1,7) and (5,5). Whereas, line 2 passes through (-1,-3) and (1,1).

It is required to find the slope of given lines and figure out whether they are perpendicular, parallel or neither.

To solve this question, first find the slope of both lines. Check if their product is equal to -1, then they are perpendicular. If the slopes are equal the lines are parallel.

Step 1 of 2

Find the slope of first line.

$$\begin{aligned}m_{1} &=\frac{5-7}{5-1} \\m_{1} &=\frac{-2}{4} \\m_{1} &=-\frac{1}{2}\end{aligned}$$

Step 2 of 2

Find the slope of first line.

$$\begin{aligned}&m_{2}=\frac{1-(-3)}{1-(-1)} \\&m_{2}=\frac{4}{2} \\&m_{2}=2\end{aligned}$$

And

$$\begin{aligned}&m_{1} m_{2}=-\frac{1}{2}(2) \\&m_{1} m_{2}=-1\end{aligned}$$

Since, both slopes are reciprocal of each other.

Therefore, the lines are perpendicular.

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nadya68 [22]

Answer:

B.) y - 6 = -8/5(x + 2)

Step-by-step explanation:

Remember in order to find the slope intercept form on 2 points, you need these equations: \frac{x_2 -x_1}{y_2 -y_1} and y-y_1=m(x-x_1)

To find the slope, you will need to use the first equation. In this case the equation will look like this: \frac{(-2)-6}{3-(-2)}=-\frac{8}{5}

Then use the second equation, plug in the numbers, and you will get B as your answer

5 0
2 years ago
Pls<br> Help me <br> I need it
ad-work [718]

Answer:

{2}^{7}

Step-by-step explanation:

{2}^{7}  = 128

{7}^{2}  = 49

So,

128 > 49 \\  {2}^{7}  \:  \:  \:  \:    >  {7}^{2}

Therefore 2^7 is greater

4 0
3 years ago
Please help me!
Alexxandr [17]

A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.

We can use the Pythagorean formula to find the other leg of the right triangle.

a²+b²=c²

Where a and b are the legs of the triangle and c is the hypotenuse.

According to the given problem,

one leg: a= 5m and hypotenuse: c=13√5 m.

So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,

5²+b²=(13√5)²

25 + b² = 13²*(√5)²

25 + b² = 169* 5

25+ b² = 845

25 + b² - 25 = 845 - 25

b² = 820

b =√ 820

b = √(4*205)

b = √4 *√205

b = 2√205

b= 2* 14.32

b = 28.64

So, b= 28.6 (Rounded to one decimal place)

Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).

5 0
3 years ago
Help me answer these PLEASE ASAP
Hoochie [10]

Answer:

Answered below

Step-by-step explanation:

<u>Sheet 1: Question 3</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠LPN = ∠OPM

7 + 13x = -20 + 16x

27 = 3x

x = 9

<u>Sheet 1: Question 4</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠ABD = ∠EBC

2x + 20 = 3x + 15

-x = -5

x = 5

<u>Sheet 1: Question 5</u>

<u>Step 1: Find the value of x</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠SOP = ∠ROQ

5x = 4x + 10

x = 10

<u>Step 2: Find angles</u>

Angle SOP = 5x = 5(10) = 50°

Angle ROQ = 50° <em>(because it is vertically opposite to angle SOP)</em>

Angle SOR = 180 - 50 <em>(because all angles on a straight line are equal to 180°)</em>

Angle SOR = 130°

Angle POQ = 130° <em>(because it is vertically opposite to angle SOR)</em>

<u>Sheet 1: Question 6</u>

Angle 1 = 72° <em>(because vertically opposite angles)</em>

∠4 + ∠1 + 41 = 180° <em>(because all angles on a straight line are equal to 180°)</em>

∠4 + 72 + 41 = 180

∠4 = 67°

∠3 = 41° <em>(because vertically opposite angles)</em>

∠2 = 67° <em>(because vertically opposite angles)</em>

<u>Sheet 2: Question 3</u>

Step 1: Find the value of x

<em>Sum of complementary angles is equal to 90°</em>

Angle A + Angle B = 90°

7x + 4 + 4x + 9 = 90°

11x = 90 - 13

11x = 77

x = 7

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 7x + 4

7(7) + 4

Angle A = 53°

Angle B: 4x + 9

4(7) + 9

Angle B = 37°

<u>Sheet 3: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>Sum of supplementary angles is equal to 180°.</em>

Angle A + Angle B = 180°

3x - 7 + 2x + 2 = 180°

5x = 185

x = 37

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 3x - 7

3(37)-7

Angle A = 104°

Angle B: 2x + 2

2(37) + 2

Angle B = 76°

<u>Sheet 3: Question 4</u>

<em>Sum of supplementary angles is equal to 180°.</em>

<u>Step 1: Find x</u>

1/4(36x-8) + 1/2(6x-20) = 180°

Take LCM

[36x - 8 + 2(6x - 20)]/4 = 180°

36x - 8 +12x - 40 = 180 x 4

48x - 48 = 720

48x = 768

x = 16

<em>Step 2: Find both angles with the help of x</em>

Angle 1: 1/4(36x-8)

1/4[36(16)-8] = 568/4

Angle 1 = 142°

Angle 2: 1/2(6x-20)

1/2[6(16)-20] = 76/2

Angle 2 = 38°

<u>Sheet 4: Question 1</u>

<em>All angles on a straight line are equal to 180°</em>

Angle z + 138° = 180°

Angle z = 180 - 138

Angle z = 42°

<u>Sheet 4: Question 2</u>

Linear pair 1: 5 and 7 <em>(because both angles are on a straight line and are equal to 180°)</em>

Linear pair 2: 6 and 8<em> (because both angles are on a straight line and are equal to 180°)</em>

<u>Sheet 4: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>All angles on a straight line are equal to 180° or linear pairs are equal to 180°</em>

Angle LMO + Angle OMN = 180°

7x + 20 + 10 + 5x = 180°

12x = 180 - 30

x = 150/12

x = 12.5

<em>Step 2: Find angles using the value of x</em>

Angle LMO: 7x + 20

7(12.5) + 20

Angle LMO = 107.5°

Angle OMN: 10 + 5x

10 + 5(12.5)

Angle OMN = 72.5°

<u>Sheet 4: Question 4</u>

<em>Linear pairs are equal to 180°.</em>

Angle 1 + Angle 2 = 180°

1/3(27x-6) + 1/2(6x-20) = 180°

<em>Take LCM = 6</em>

[2(27x-6) + 3(6x-20)]/6 = 180

54x - 12 + 18x - 60 = 1080

72x - 72 = 1080

72x = 1152

x = 16

!!

7 0
3 years ago
5. Two vertices of a rectangle are (8,-5) and (8,7). If the area of the rectangle is 72 square units, name the possible location
Phantasy [73]

Answer:

<h3>#5</h3>

<u>Given vertices:</u>

  • (8, -5) and (8, 7)

These have same x-coordinate, so when connected form a vertical segment.

<u>The length of the segment is:</u>

  • 7 - (-5) = 12 units

The area of the rectangle is 72 square units, so the horizontal segment has the length of:

  • 72/12 = 6 units

<u>Possible location of the remaining vertices (to the left from the given):</u>

  • (8 - 6, -5) = (2, -5)

and

  • (8 - 6, 7) = (2, 7)
<h3>#6</h3>

<u>Similarly to previous exercise:</u>

  • (5, -8) and (5, 4) given with the area of 48 square units

<u>The distance between the given vertices:</u>

  • 4 - (-8) = 12 units

<u>The other side length is:</u>

  • 48/12 = 4 units

<u>Possible location of the other vertices (to the right from the given):</u>

  • (5 + 4, -8) = (9, -8)

and

  • (5 + 4, 4) = (9, 4)
4 0
3 years ago
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