I need help, how do i solve the equations and get the degree for the circle

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

6 0

The answer is 130
3x-70=x+10
3x=x+80
2x=80
X=40

qwelly [4]3 years ago

4 0

Answer:

D 130º

Step-by-step explanation:

3x-70=x+10

so 2x-70=10

x=40

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wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0

Andreyy89

Answer:

$E_n=34,467,075.42\ N/C$

Step-by-step explanation:

Electric Field

The electric field produced by a point charge Q at a distance d is given by

$\displaystyle E=K\cdot \frac{Q}{d^2}$

Where

$K = 9\cdot 10^9\ Nw.m^2/c^2$

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge $q_1=+6.24\mu C=6.24\cdot 10^{-6}C$ is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

$\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}$

$E_1=37,888,345.42\ N/C$

Similarly, for $q_2=-9.55\mu C=-9.55\cdot 10^{-6}C$ , the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right: