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RideAnS [48]
2 years ago
11

At Trendy Tailor Boutique's annual end-of-season sale, every necktie in the

Mathematics
1 answer:
astra-53 [7]2 years ago
5 0

By direct calculation, we will see that the full price of each necktie is $29.

<h3>How to find the complete price of each necktie?</h3>

Let's say that the full price of each necktie is f.

We know that Will each necktie costed $8 less than the full price, so he paid:

(f - $8) for each one.

Knowing that he bought 7 and paid a total of $147, we know that he paid:

$147/7 = $21

Then we need to solve:

(f - $8) = $21

Solving for f, we have:

f = $21 + $8 = $29.

So the full price of each necktie is $29.

If you want to learn more about algebra, you can read:

brainly.com/question/4344214

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What is 2and 2/3 divided by 4/5
Illusion [34]

Answer:

\frac{10}{3}  

I hope this helps!

5 0
3 years ago
(b) dy/dx = (x - y+ 1)^2
Elanso [62]

Substitute v(x)=x-y(x)+1, so that

\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}

Then the resulting ODE in v(x) is separable, with

1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx

On the left, we can split into partial fractions:

\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx

Integrating both sides gives

\dfrac{\ln|1-v|+\ln|1+v|}2=x+C

\dfrac12\ln|1-v^2|=x+C

1-v^2=e^{2x+C}

v=\pm\sqrt{1-Ce^{2x}}

Now solve for y(x):

x-y+1=\pm\sqrt{1-Ce^{2x}}

\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}

3 0
3 years ago
When you form general ideas and rules based on your experiences and observations you call that form of reasoning
lutik1710 [3]

You could probably call it INDUCTION

8 0
3 years ago
Read 2 more answers
ASAP ANSWER PLEASE
Liula [17]

Answer:

y = 2x -8

Step-by-step explanation:

The slope intercept form for a line is

y = mx+b where m is the slope and b is the y intercept

y = 2x -8

5 0
3 years ago
The bottom portion of a loading bin is cone shaped. The base radius of this part of the bin is 3.5 feet and the slant height is
jek_recluse [69]

\bf \textit{lateral surface of a cone}\\\\ LA=\pi r\sqrt{r^2+h^2}~~ \begin{cases} ~~ r=radius\\ sh=\stackrel{slant~height}{\sqrt{r^2+h^2}}\\[-0.5em] \hrulefill\\ r=3.5\\ sh=6.5 \end{cases}\\\\\\ LA=\pi (3.5)(6.5)\implies LA\approx71.47 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{sh}{6.5}=\sqrt{r^2+h^2}\implies 6.5=\sqrt{3.5^2+h^2}\implies 6.5^2=3.5^2+h^2 \\\\\\ 6.5^2-3.5^2=h^2\implies \sqrt{6.5^2-3.5^2}=h\implies \sqrt{30}=h \\\\[-0.35em] ~\dotfill

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3.5\\ h=\sqrt{30} \end{cases}\implies V=\cfrac{\pi (3.5)^2\sqrt{30}}{3}\implies V\approx 70.26

7 0
3 years ago
Read 2 more answers
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