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RideAnS [48]
3 years ago
11

At Trendy Tailor Boutique's annual end-of-season sale, every necktie in the

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

By direct calculation, we will see that the full price of each necktie is $29.

<h3>How to find the complete price of each necktie?</h3>

Let's say that the full price of each necktie is f.

We know that Will each necktie costed $8 less than the full price, so he paid:

(f - $8) for each one.

Knowing that he bought 7 and paid a total of $147, we know that he paid:

$147/7 = $21

Then we need to solve:

(f - $8) = $21

Solving for f, we have:

f = $21 + $8 = $29.

So the full price of each necktie is $29.

If you want to learn more about algebra, you can read:

brainly.com/question/4344214

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What is 4 ten thousands 4 thousands times ten
andreyandreev [35.5K]

Answer:

your question dosent make sense. theres no such thing as 4 ten thousands

Step-by-step explanation:

4 0
3 years ago
2.943÷2.7 any help???
Zinaida [17]

The answer will be 1.09. Hope this will help you!

6 0
4 years ago
Read 2 more answers
The function C(F) =5/9 (F - 32) is used to convert temperature from Fahrenheit (F) to Celsius (C).
mr Goodwill [35]

Answer:

K(F) = 5/9 (F - 32) + 273.15

K(F)=298.15k

Step-by-step explanation:

C(F) =5/9 (F - 32) is used to convert temperature from Fahrenheit (F) to Celsius (C).

C(F) =5/9 (F - 32)

The function K(C)= C + 273.15 is used to convert temperature from Celsius (C) to the Kelvin (K) scale.

K(C)= C + 273.15

K(c) - 273= C

Equating both values of C

K(F) - 273.15=5/9 (F - 32)

K(F) = 5/9 (F - 32) + 273.15

If F = 77°F

K(F) = 5/9 (F - 32) + 273.15

K(F) = 5/9(77-32) + 273.15

K(F) = 5/9(45) +273.15

K(F) = 25+273.15

K(F)=298.15k

4 0
3 years ago
For the triangles to be congruent by HL, what must be the value of x?
lilavasa [31]

Answer:

x = 8

Step-by-step explanation:

For the triangles to be congruent, then the legs

ED = AB, that is

4x + 2 = 34 ( subtract 2 from both sides )

4x = 32 ( divide both sides by 4 )

x = 8

6 0
4 years ago
Solve the equation on the interval 0 less than or equals theta less than 2 pi .0≤θ&lt;2π. secant StartFraction 5 theta Over 4 En
qaws [65]

Answer:  4π/15, 4π/3 and 28π/15 (in radians)

Step-by-step explanation:

sec 5\theta/4 =2

Recall that sec \theta = 1/cos \theta

1/cos (5\theta/4) =2

cos (5\theta/4) =1/2

Cos^{-1} \frac{1}{2} = 5\theta/4

This implies that

\mp60+360n=5\theta/4

\theta=4/5(\mp60+360n)= \mp48+288n

When  n=0, \theta=48

When  n=1, \theta=240, 336

Therefore the values of \theta between 0 and 2π are 48, 240 and 336. (All in degrees)

48 degrees= 4π/15 rad

240 degrees =4π/3 rad

336 degrees = 28π/15 rad

5 0
3 years ago
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