Answer:
0.5372
Step-by-step explanation:
Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.
Let X be the no of births in the hospital per hour
X is Poisson
with mean = 1.8
the probability of observing at least two births in a given hour at the hospital
= 
the probability of observing at least two births in a given hour at the hospital = 0.5372
Answer:
Step-by-step explanation:
13p⁵ + 6p - 12p² -(-9p - p² - 13p⁵) = 13p⁵ + 6p - 12p² + 9p + p² + 13p⁵
{Distribute (-1) to the second expression}
= <u>13p⁵ + 13p⁵</u> <u>-12p² + p²</u> <u>+ 6p + 9p</u>
{Combine like terms}
= 26p⁵ - 11p² + 15p
X = dull pencils
y = sharp pencils
x + y = 100
y = x + 16 ~~Plug this back into your original x+y equation.
x+x+16=100 ==> 2x = 84 ==> x = 42. Plug this back into the y = equation
y = 42 + 16 ==> y = 58.
42 Dull, 58 sharp.
5/0 UNDEFINED... The answer is a vertical line.
This statement is true because you multiply the exponents. 4 x 2 is equal to 8
