We can figure out how many numbers there are from 368 to 500 by subtracting.
500 - 368 = 132
Now, we need to get it in word form. This can be done by looking at the place value of each number.. So your answer would be:
1 hundred, 3 tens, and 2 ones.
A common stock
a preferred stock
a bond in a stable foreign goverment
Answer:42
Step-by-step explanation:
Answer: A
Step-by-step explanation:
- Open circle means that x does not equal that number. For example, the open circle on C is on 8, so that shows x is not equal to 8.
- Closed circle means that x does equal that number. For example on A, there is a closed circle on 8, so x could equal 8.
First, we need to solve the equation.
- Subtract 200 frim 1200 -> 125x ≥ 1000.
- Divide 125 from 1000 to isolate the x -> x ≥ 8
So, that means x is bigger than or equal to 8.
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:
<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.
<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.
If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.
