T_n = 3 * T_(n-1)
Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1
T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!
Short way (sometimes it works!)
T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648
4x = 157.2
4x/4 = 157.2/4
x = 39.3
The answer is 3h.
Because 3h is like 3 x H
Answer:
11^3/5
Step-by-step explanation:
The exponent of 3 becomes the numerator while the 5 in the root becomes the denominator which creates the fraction 3/5. So the final answer is 11^3/5