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vredina [299]
3 years ago
15

What is the difference between ordered list and unordered list?

Computers and Technology
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

In an ordered list, each item is displayed along with the numbers or letters instead of bullets

In an unordered list, each item is displayed with a bullet.

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Complete the sentence
prisoha [69]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is: Online community technologies.

So, we can fill this question with the correct option as below:

<u>Online community technologies</u> are technologies that support virtual communities and the sharing of content with friends and family.

As we know that online community technologies are those technologies where people of the same group or interest make community virtually online. Where they can share their contents such as pictures, videos, thaught, ideas, etc with the group or family members.

There are different technologies that support virtual communities to share content with friends and family.

Such as Zoom meetings, Sk ype, Face book, Insta gram etc.

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If I want to add a new slide to my presentation, which option would I click on?
ivanzaharov [21]
The answer would be D. New Slide
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3 years ago
File Sales.java contains a Java program that prompts for and reads in the sales for each of 5 salespeople in a company. It then
myrzilka [38]

Answer:

import java.util.Scanner;

public class Sales

{

public static void main(String[] args) {

   

    int sum;

    Scanner input = new Scanner(System.in);

   

    System.out.print("Enter number of salespeople: ");

    int salespeople = input.nextInt();

    int[] sales = new int[salespeople];

       

    for (int i=0; i<sales.length; i++)

    {

     System.out.print("Enter sales for salesperson " + (i+1) + ": ");

     sales[i] = input.nextInt();

    }

    System.out.println("\nSalesperson   Sales");

    System.out.println("--------------------");

    sum = 0;

       int maxSale = sales[0];

       int minSale  = sales[0];

       int minId=1;

       int maxId=1;

    for (int i=0; i<sales.length; i++)

    {

               System.out.println("     " + (i+1) + "         " + sales[i]);

 sum += sales[i];

  if(maxSale < sales[i])

           {

               maxSale = sales[i];

               maxId = i+1;

           }

           if(minSale > sales[i])

           {

               minSale = sales[i];

               minId = i+1;

           }

   }

System.out.println("Total sales: " + sum);

       System.out.println("The average sale is: " + sum / salespeople );

       System.out.println("Salesperson "+ maxId + " had the highest sale with "+ maxSale + ".");

       System.out.println("Salesperson "+ minId + " had the lowest sale with "+ minSale + ".");

       

       int amount = 0;

       int counter = 0;

       System.out.print("Enter an amount: ");

       amount = input.nextInt();

       for (int i=0; i<sales.length; i++)

    {

     if(sales[i] > amount) {

         counter++;

         System.out.println("Salesperson "+ (i+1) + " exceeded given amount. (Number of sales: " + sales[i] +")");

     }

    }

       System.out.println("Number of salespeople exceeded given amount is: "+ counter);

}

}

Explanation:

- Ask the user for the number of salesperson

- According to entered number, create an array called sales to hold sale number for each person

- In the first for loop, assign the given sales numbers

-  In the second for loop, print all the sales people with sales, calculate the total sales. Also, find the minimum and maximum sales numbers with associated individuals.

- Print total, average, highest, and lowest sales.

- Ask user enter an amount

- In the third for loop, find the sales people who exceeded this amount.

- Print number of sales people who exceeded the amount.

8 0
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​Lara is the chief editor of "Laughter and Life," an online magazine. Lara has assigned Jenny the task of redesigning the magazi
Zarrin [17]

Answer:

The "A" option is correct.

Explanation:

For CSS flexbox layout, the property "align-content" requires that the space in the flexbox is more than enough to show the items. In this case, to distribute evenly the items and show the first and last items aligned with the start and end of the main axis, the only suitable option is "space-between". This option leaves no space at the start or at the end of the flexbox, distributing the remaining space between the elements into the flexbox.

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Alexis received paychecks from both her jobs and she would like to deposit them. One check is for $62.88 and the other is $523.2
Karolina [17]

Answer:

something :}

Explanation:

have a good day

8 0
3 years ago
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