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2 years ago

Any help would rlly appreciate it

Mathematics

1 answer:

Scrat [10]2 years ago

7 0

Go to khan academy they show you how

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Triangle CDE is an isosceles triangle with angle d congruent to angle E if CD= 4x+9, DE= 7x-5, CE= 16x-27, find x and the measur

Montano1993 [528]

ANSWER

$x = 3$
$CD= 21 \: units$
$DE= 16 \: units$

$CE= 21 \: units$

EXPLANATION

It was given that ∆CDE is an isosceles triangle.

The length of the sides are given in terms of x as follows.

$CD=4x+9$

$DE=7x-5$

$CE=16x-27$

It was also given that, angle D is congruent to angle E.

This implies that, side CD and CE are equal.

Thus,

$|CD| = |CE|$
In terms of x, we have;

$4x + 9 = 16x - 27$

We group like terms to get,

$16x - 4x = 9 + 27$

$12x = 36$

Divide both sides by 12 to get,

$x = \frac{36}{12}$

$\therefore \: x = 3$

The length of the sides are;

$CD=4(3)+9 = 21 \: units$

$DE=7(3)-5 = 16 \: units$

$CE=16(3)-27 = 21 \: units$

3 0

3 years ago

PLZZZ HELP ME WITH THESE 4 QUESTIONS <br><br> THX SO MUCH!! ( 80 POINTSSSSS!!!!)

katrin2010 [14]

For section 3.01 black, number 1 is correct, but number 2 is wrong.

When you raise an exponent to an exponent, you multiply the 2 exponents.

(x^4)^5 is x^20.

Number 3 is also right.

For 3.02, you use the interest formula. (1 + i/100)^t times x

x is the amount of money you have originally. i is the interest rate, t is the time.

1,500(1.03)^5 = 1738.91111145

$1738.91

For section 3.01 red in fractional exponents the numerator are the powers and the denominator is the root.

$\sqrt[4]{a^{3} } = a^{\frac{3}{4} }$

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2 years ago

For f(x) = 2x+1 and g(x) = x+14, find (gof)(x).

Goryan [66]

Answer: OPTION B

Step-by-step explanation:

You can observe that the exercise provides you two Linear functions.

The first Linear function is the function f(x). This is:

$f(x) = 2x+1$

And the other Linear function is the function g(x):

$g(x) = x+14$

In order to find $(gof)(x)$ , you need to follow these steps shown below:

<u>Step 1</u>:

You must substitute the function f(x) into the function g(x); this means that the function f(x) will be in the place of the variable "x" of the function g(x); as you can observe below:

$(gof)(x) = (2x+1)+14$

<u>Step 2</u>:

Finally you must combine the like terms (You can notice that the like terms are 1 and 14; then you must add them). Therefore, you get that $(gof)(x)$ is:

$(gof)(x) = 2x+1+14\\\\(gof)(x) = 2x+15$