4.01 grams of Licl are needed to release this amount of heat
<h3>What does one gram weigh?</h3>
The gram is a unit of mass in the International System of Units (SI) that is equal to one thousandth of a kilogram. It was originally known as the gramme. Gram. This pen cap weighs around one gram. A weight scale like this one may provide a precise mass readout for many different things.
Mass of Licl required to release 5850J of heat to the surroundings.
Let x g Licl required.
Then x g ×∆H = 5850J
x g × 1.46 × 10³ = 5850
x = 5850/ 1.46 × 10³
x = 4.0068
so 4.01g Licl required.
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The answer is B I hope this helps you
Answer:
D. The particles move up and down without changing their position
Explanation:
These are gases. They are typically known for their randomness and no fixed arrangement of their atoms.
Gases generally assume the volumes of the containers they fill. They spread easily and readily to fill the volume where they occupy. Also, gases are readily compressible as they lack intermolecular attraction between their molecules.
Answer:
a) V = 1.542 E11 ft³
b) V = 4367011968 m³
c) V = 1.1535 E12 us gal
Explanation:
Acre surface is defined as 66 by 660 feet at a depth of one foot:
⇒ Vacre-foot = 66ft*660ft*1ft = 43560 ft³
lake:
a) V = 3.54 E6 acre-feet * ( 43560 ft³ / acre-foot ) = 1.542 E11 ft³
b) V = 1.542 E11 ft³ * ( 0.02832m³ / ft³ ) = 4367011968 m³
c) V = 1.542 E11 ft³ * ( 7.48052 us gal/ft³ ) = 1.1535 E12 us gal
