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Vitek1552 [10]
2 years ago
11

What is the molar mass of the imaginary compound Z(AX3)2

Chemistry
1 answer:
astra-53 [7]2 years ago
7 0

The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.

<h3>How do we calculate molar mass?</h3>

Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.

Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:

Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)

Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.

To know more about molar mass, visit the below link:

brainly.com/question/18983376

#SPJ1

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Explain how dalton's theory of the atom and the conservation of mass are related
Scorpion4ik [409]

Answer:

Dalton's atomic theory states that atoms may be mixed in certain rations to produce compounds, while the law of conservation of mass states that the mass of reactants equals the mass of products. They are related because in the production of compounds, Dalton made it clear that mass can neither be destroyed or created, which supports the conservation of mass law.

Explanation:^^^

Hoped it helped...

8 0
3 years ago
What does density have to do with the cycling of matter in earths interior
Anastaziya [24]

Answer:

The rocks of higher density inter the mantle. Due to density they sink and melt. When they melt the density decreases and rises to the top. They then are recycled through volcanoes.  

Explanation:

8 0
3 years ago
Which of the following chemical reactions represents an acid-base reaction?
LenKa [72]

Answer:

HBr + KOH -> KBr + H₂O

Explanation:

Acid-base reactions always produce a salt [KBr] and water [H₂O].

5 0
2 years ago
A radioactive element reduces to 5.00% of its initial mass in
Stolb23 [73]

The half-life in months of a radioactive element that reduce to 5.00% of its initial mass in 500.0 years is approximately 1389 months

To solve this question, we'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

Amount remaining (N) = 5%

Original amount (N₀) = 100%

<h3>Number of half-lives (n) =?</h3>

N₀ × 2ⁿ = N  

5 × 2ⁿ = 100

2ⁿ = 100/5

2ⁿ = 20

Take the log of both side

Log 2ⁿ = log 20

nlog 2 = log 20

Divide both side by log 2

n = log 20 / log 2

<h3>n = 4.32</h3>

Thus, 4.32 half-lives gas elapsed.

Finally, we shall determine the half-life of the element. This can be obtained as follow.

Number of half-lives (n) = 4.32

Time (t) = 500 years

<h3>Half-life (t½) =? </h3>

t½ = t / n

t½ = 500 / 4.32

t½ = 115.74 years

Multiply by 12 to express in months

t½ = 115.74 × 12

<h3>t½ ≈ 1389 months </h3>

Therefore, the half-life of the radioactive element in months is approximately 1389 months

Learn more: brainly.com/question/24868345

8 0
2 years ago
What is the pH of a solution with a hydronium concentration of 0.36 M?
kodGreya [7K]

Answer:

<h2>0.44 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H_3O}^{+}]

From the question we have

pH =  -  log(0.36)  \\  = 0.4436...

We have the final answer as

<h3>0.44</h3>

Hope this helps you

8 0
3 years ago
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