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2 years ago

What is the least common multiple? (6 and 12)

1 answer:

6 0

Answer:Least common multiple ( LCM ) of 6 and 12 is 12. LCM(6,12) = 12. Least common multiple or lowest common denominator (lcd) can be calculated in two way; with the LCM formula calculation of greatest common factor (GCF), or multiplying the prime factors with the highest exponent factor.

Step-by-step explanation:

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Try it .............

Veseljchak [2.6K]

Step 1: 3

Step 2: 6

Step 3: 16

Step 4: 8

Step 5: 5

Nice

7 0

3 years ago

Read 2 more answers

Triangles ABC and XYZ are shown below. A student knows that AX and 2cm 22. The student claims that AABC is similar to AXYZ

bezimeni [28]

sorry i couldn't answer tho

7 0

3 years ago

Solve for b, then solve for each angle in the triangle

lesya692 [45]

We know that the sum of the interior angles of a triangle equals 180, then,in this case we have the following equation:

$b+2b+(b+16)=180$

then, solving for b, we get:

$\begin{gathered} b+2b+(b+16)=180 \\ \Rightarrow4b+16=180 \\ \Rightarrow4b=180-16=164 \\ \Rightarrow b=\frac{164}{4}=41 \\ b=41 \end{gathered}$

now that we have that b = 41, we can find the measure of each angle:

$\begin{gathered} b=41 \\ 2b=2(41)=82 \\ b+16=41+16=57 \end{gathered}$

7 0

7 months ago

Triangle TRE has vertices T(3,6), R(-3,10), and E(-9,4). Find the coordinates of point M if line TM is a median of triangle TRE

Sergeeva-Olga [200]

Answer:

The coordinate of point M = (-6,7)

Explanation:

The Median of a triangle is a line segment from a vertex to the midpoint of the opposite side of a triangle.

Given: $\triangle TRE$ has vertices T(3,6) , R(-3,10) and E(-9,4).

Here, line TM is a median of triangle TRE where M is the midpoint of RE.

The midpoint of M of the line segment from R(-3,10) to E(-9,4) is;

M = $(\frac{-3+(-9)}{2}, \frac{10+4}{2}) = ( \frac{-12}{2}, \frac{14}{2} )=(-6,7)$

Therefore, the coordinate of point M is, (-6,7).

7 0

2 years ago

Help me now plsss! can't think this one out.

ra1l [238]

She worked 30 hours per week.

The problem turns out to be the following:
2x+15=3x-15.
First you need to have only one x variable so you subtract the X's:
3x-2x=X
The problem now turns into 15=x-15.
You have to isolate the X so you do x+15. You have to do the same to the other side so 15+15=30, therefore x=30

8 0

2 years ago

What is the least common multiple? (6 and 12)​

What is the least common multiple? (6 and 12)