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3 years ago

Hep yep help helphelp

Mathematics

1 answer:

iragen [17]3 years ago

6 0

Answer:

pretty sure it's A

Step-by-step explanation:

cuz a common factor of 9 and 10 is 90 do the calculations and it should be simple.

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David measured the height of a window frame as 5.61 feet, but the actual height was 6 feet. What is the percentage of error in D

kirill [66]

0.39% is David's measurement

4 0

3 years ago

Read 2 more answers

School 1: minimum:68, Q1=77, median=83, Q3=86, maximum=95

vlada-n [284]

In school 1, 50% of the students scored above 83 and in school 2, 50% of the class scored above 81.
In school 1, 25% of the students scored above 86 and in school 2, 25% of the class scored above 85.
In school 1, 25% of the students scored below 77 and in school 2, 25% of the class scored below 73.
The minimum score for school 1 is 68 while that of school 2 is 65.
The maximum score for school 1 is 95 while that of school 2 is 98.

In all this measures of center, the data from both schools are close together, so we can conclude that both schools did abut the same on the test.

6 0

3 years ago

out of of are 40 students, 15 are on the student council. what percent of the students are NOT on the student council?

saw5 [17]

40-15=25 students not on student council

25/40 = .625 decimal

multiply by 100 to get percent

62.5% of students are not on student council

Estimating:

15 rounds to 20 and 40 rounds to 50

40% are in student council and that leaves roughly 60% not in student council.

6 0

3 years ago

Find each percent increase round to the nearest percent from $5 to $8

IRISSAK [1]

There are at least a few ways to do it, one of them being:

$8 - $5 = $3, so we may want to find out how much percent of 5 is 3.

3 = x% of 5
3 = x/100 * 5
3 = x/20 * 1
3 = x/20 / * 20 (both sides)
x = 60 [percent]

So now we know that 3 is 60% of 5. It also means that the increase from $5 to $8 was by <u>60%</u><u />.

6 0

4 years ago

You roll 2 dice. If the sum of the dice is: 2, 3, 4 you win $20. If the sum is 5, 6, 7, 8 you win $10. If the sum is 9, 10, 11 y

Elis [28]

Answer:

1) The expected value of the "winnings" is $(-0.97 $\overline 2$ )

2) The variance for the "winnings" is $0.57966

3) The standard deviation for the "winnings" is$0.761354

4) The game is not a fair game because one is expected to lose $0.97 $\overline 2$

Step-by-step explanation:

1) The probability of having a sum of 2 = 1/6×1/6 = 1/36

The probability of having a sum of 3 = 1/6×1/6 = 1/36

The probability of having a sum of 4 = 1/6×1/6 + 1/6×1/6 = 1/18

The probability of having a sum of 5 = 1/6×1/6 + 1/6×1/6 = 1/18

The probability of having a sum of 6 = 1/6×1/6 + 1/6×1/6 + 1/6×1/6 = 1/12

The probability of having a sum of 7 = 1/6×1/6 + 1/6×1/6 + 1/6×1/6 = 1/12

The probability of having a sum of 8 = 1/6×1/6 + 1/6×1/6 + 1/6×1/6 = 1/12

The probability of having a sum of 9 = 1/6×1/6 + 1/6×1/6 = 1/18

The probability of having a sum of 10 = 1/6×1/6 + 1/6×1/6 = 1/18

The probability of having a sum of 11 = 1/6×1/6 = 1/36

The probability of having a sum of 12 = 1/6×1/6 = 1/36

The values are;

For 2, we have 1/36 × (20 - 5) = 0.41 $\overline 6$

For 3, we have 1/36 × (20 - 5) = 0.41 $\overline 6$

For 4, we have 1/18 × (20 - 5) = 0.8 $\overline 3$

For 5, we have 1/18 × (10 - 5) = 0.2 $\overline 7$

For 6, we have 1/12 × (10 - 5) = 0.41 $\overline 6$

For 7, we have 1/12 × (10 - 5) = 0.41 $\overline 6$

For 8, we have 1/12 × (10 - 5) = 0.41 $\overline 6$

For 9, we have 1/18 × (-20 - 5) = -1.3 $\overline 8$

For 10, we have 1/18 × (-20 - 5) = -1.3 $\overline 8$

For 11, we have 1/36 × (-20 - 5) = -0.69 $\overline 4$

For 12, we have 1/36 × (-25 - 5) = -0.69 $\overline 4$

The expected value of the winnings is given as follows;

0.41 $\overline 6$ + 0.41 $\overline 6$ + 0.8 $\overline 3$ + 0.8 $\overline 3$ + 0.8 $\overline 3$ + 0.41 $\overline 6$ + 0.41 $\overline 6$ + -1.3 $\overline 8$ -1.3 - 0.69 $\overline 4$ - 0.69 $\overline 4$ = -0.97 $\overline 2$

Therefore, the expected value = $-0.97 $\overline 2$ , which is one is expected to lose $0.97 $\overline 2$

2) Using Microsoft Excel, we have;

The variance for the "winnings", σ² = $0.57966

3) The standard deviation for the "winnings" = √σ² = √(0.57966) ≈ $0.761354

4) The game is not a fair game because one is expected to lose $0.97 $\overline 2$

3 0

3 years ago